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3 years ago

Solve for x. 8 + x = -4

Mathematics

2 answers:

Verizon [17]3 years ago

7 0

Answer:

x=-12

Step-by-step explanation:

because 8-12 geta you -4

Lady_Fox [76]3 years ago

3 0

Answer: X= -4.8

Step-by-step explanation:Simplifying

0.8 + x = -4

Solving

0.8 + x = -4

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-0.8' to each side of the equation.

0.8 + -0.8 + x = -4 + -0.8

Combine like terms: 0.8 + -0.8 = 0

0 + x = -4 + -0.8

x = -4 + -0.8

Combine like terms: -4 + -0.8 = -4.8

x = -4.8

Simplifying

x = -4.8

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3 years ago

Suppose that an insect population’s density, in thousands per acre, during year n, can be modeled by the recursive formula: a1 =

vlabodo [156]

Answer:

The population alternates between increasing and decreasing

Step-by-step explanation:

The options of the question are

A) The population density decreases each year.

B) The population density increases each year.

C) The population density remains constant.

D) The population alternates between increasing and decreasing

we have

$a_n=2.9(a_n_-_1)-0.2(a_n_-_1)^2$

$a_1=8$

Find the value of $a_2$

For n=2

$a_2=2.9(a_1)-0.2(a_1)^2$

$a_2=2.9(8)-0.2(8)^2=10.4$

Find the value of $a_3$

For n=3

$a_3=2.9(a_2)-0.2(a_2)^2$

$a_3=2.9(10.4)-0.2(10.4)^2=8.528$

For n=4

$a_4=2.9(a_3)-0.2(a_3)^2$

$a_4=2.9(8.528)-0.2(8.528)^2=10.1858$

For n=5

$a_5=2.9(a_4)-0.2(a_4)^2$

$a_5=2.9(10.1858)-0.2(10.1858)^2=8.7887$

therefore

The population alternates between increasing and decreasing

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o-na [289]

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