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Lena [83]
3 years ago
11

If a website ends with .gov does it mean that its written by the government or?

Computers and Technology
2 answers:
Soloha48 [4]3 years ago
7 0
Umm... No. (I'm pretty sure)
Lena [83]3 years ago
3 0
Yes, it's sponsored by the government
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c++ Write a statement that increments (adds 1 to) one and only one of these five variables: reverseDrivers parkedDrivers slowDri
Mazyrski [523]

Answer:

The following statement are:

if(speed < 0) // if statement

{

reverseDrivers++; //if the speed is less than 0, then increment in "reverseDrivers"

}

else if(speed < 1) //else if statement

{

parkedDrivers++; //speed is less than 1, than increments in "parkedDrivers"

}

else if(speed < 40)

{

slowDrivers++; //speed is less then 40, than increment in "slowDriver"

}

else if(speed <= 65)

{

safeDrivers++; //speed is less than or equal to 40, then increment in "safeDriver"

}

else

{

speeders++; //else increment in speeders

}

Explanation:

From the following statement their are certain condition arises

If the speed is less than 0, then increments the “reverseDrivers” variable by 1.

If the speed is less than 1, then increments the “parkDriver” variable by 1.

If speed is less than 40, then increment in "slowDriver" variable by 1.

If speed is less than or equal to 40, then increment in "safeDriver" variable by 1.

Otherwise increment in "speeders"

7 0
3 years ago
An administrator needs to make sure that video conferencing is allocated a high portion of bandwidth within a company network. W
frosja888 [35]

Answer:

QoS

Explanation:

We could use a blacklisting or a MAC filtering to remove from the network, and in this way, we're going to get a high portion of bandwidth, but other must work too, and the whitelisting have almost the same function, but QoS Quality of service is specifically for these cases where we need high bandwidth for a video conference, we can make this with some tools or techniques like jitter buffer and traffic shaping.

4 0
3 years ago
To make a drop shadow larger what should you change about the drop shadow in gimp
vlabodo [156]
To Change the Drop Shadow Just Go to effects on the photo go to drop shadow than change the spread and Distinse and Opasity.
4 0
3 years ago
Which property describes if a mineral breaks down into flatpieces​
marta [7]

Answer: Cleavage

Explanation:

3 0
3 years ago
1. The following programs require using arrays. For each, the input comes from standard input and consists of N real numbers bet
Mamont248 [21]

Answer:

import java.util.*;

import java.io.BufferedReader;

import java.io.IOException;

import java.io.InputStreamReader;

import java.util.Arrays;

class GFG

{

  // Function for calculating mean

  public static double findMean(double a[], int n)

  {

      int sum = 0;

      for (int i = 0; i < n; i++)

          sum += a[i];

 

      return (double)sum / (double)n;

  }

  // Function for calculating median

  public static double findMedian(double a[], int n)

  {

      // First we sort the array

      Arrays.sort(a);

      // check for even case

      if (n % 2 != 0)

      return (double)a[n / 2];

 

      return (double)(a[(n - 1) / 2] + a[n / 2]) / 2.0;

  }

  public static double findMode(double a[], int n)

{

// The output array b[] will

// have sorted array

//int []b = new int[n];

 

// variable to store max of

// input array which will

// to have size of count array

double max = Arrays.stream(a).max().getAsDouble();

 

// auxiliary(count) array to

// store count. Initialize

// count array as 0. Size

// of count array will be

// equal to (max + 1).

double t = max + 1;

double[] count = new double[(int)t];

for (int i = 0; i < t; i++)

{

count[i] = 0;

}

 

// Store count of each element

// of input array

for (int i = 0; i < n; i++)

{

count[(int)(10*a[i])]++;

}

 

// mode is the index with maximum count

double mode = 0;

double k = count[0];

for (int i = 1; i < t; i++)

{

if (count[i] > k)

{

k = count[i];

mode = i;

}

}

return mode;

}

public static double findSmallest(double [] A, int total){

Arrays.sort(A);

return A[0];

}

 

public static void printAboveAvg(double arr[], int n)

{

 

// Find average

double avg = 0;

for (int i = 0; i < n; i++)

avg += arr[i];

avg = avg / n;

 

// Print elements greater than average

for (int i = 0; i < n; i++)

if (arr[i] > avg)

System.out.print(arr[i] + " ");

System.out.println();

}

 

public static void printrand(double [] A, int n){

Arrays.sort(A);

for(int i=0;i<n;i++){

System.out.print(A[0]+"/t");

}

System.out.println();

}

 

public static void printHist(double [] arr, int n) {

 

for (double i = 1.0; i >= 0; i-=0.1) {

System.out.print(i+" | ");

for (int j = 0; j < n; j++) {

 

// if array of element is greater

// then array it print x

if (arr[j] >= i)

System.out.print("x");

 

// else print blank spaces

else

System.out.print(" ");

}

System.out.println();

}

// print last line denoted by ----

for(int l = 0; l < (n + 3); l++){    

System.out.print("---");

}

 

System.out.println();

System.out.print(" ");

 

for (int k = 0; k < n; k++) {

System.out.print(arr[k]+" ");

}

}

  // Driver program

  public static void main(String args[]) throws IOException

  {

      //Enter data using BufferReader

BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

double [] A = new double[100];

int i=0;

System.out.println("Enter the numbers(0.0-1.0) /n Enter 9 if u have entered the numbers. /n");

do

{

A[i++]=Double.parseDouble(br.readLine());

}while(A[i-1]==9);

      i--;

      System.out.println("Average = " + findMean(A,i) );

      System.out.println("Median = " + findMedian(A,i));

      System.out.println("Element that occured most frequently = " + findMode(A,i));

      System.out.println("number closest to 0.0 =" + findSmallest(A,i));

      System.out.println("Numbers that are greater than the average are follows:");

      printAboveAvg(A,i);

      System.out.println("Numbers in random order are as follows:");

      printrand(A,i);

      System.out.println("Histogram is bellow:");

      printHist(A,i);

  }

}

Explanation:

3 0
3 years ago
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