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3 years ago

Is it's an isosceles trapezoid? how do you know???

Mathematics

2 answers:

NNADVOKAT [17]3 years ago

7 0

Your answer would be, Yes! It is an Isosceles Trapezoid, Because, Isosceles trapezoids have at least one set of opposite sides, that are parallel, mainly the base, and it's opposite. The non-base sides are equal in length to each other, and the base angles are equal to each other.

Hope that helps!!!!!!

kkurt [141]3 years ago

3 0

Answer:

Yes, it is an isosceles trapezoid. In an isosceles trapezoid, its non-parallel sides make equal angles with the base and the two sides are equal.

Step-by-step explanation:

A trapezoid is a 3 dimensional figure formed from trapezium. It is a quadrilateral with one pair of parallel sides to be equal and a line of symmetry bisecting one pair of opposite sides.

A trapezoid with the two non-parallel sides the same length is called an isosceles trapezoid. Its non parallel sides make equal angles with the base.

Therefore, the rough sketch shows an isosceles trapezoid.

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3 years ago

If<br> 2/9<br> of an amount is equal to 14, what is the whole amount equal to

Alex

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3 years ago

Convert r =-72/12+6 sin theta to Cartesian form.

PolarNik [594]

For converting polar to cartesian form we know
$r = \sqrt{x^2 + y^2}$
$x = rcos \theta , y = rsin \theta$

Given equation is

$r = \frac{-72}{12} + 6sin \theta$

We can simplify it as
$r = -6 + 6sin \theta$

Now we can write it as
$r^2 = -6r + 6rsin \theta$

Now we can use
$r^2 = x^ 2+ y^2 , rsin \theta = y , r = \sqrt{x^2 + y^2}$
So equation we can write it as
$x^2 + y^2 = -6 \sqrt{x^2 + y^2} + 6y$
$x^2 + y^2 - 6y = -6 \sqrt{x^2 + y^2}$
On squaring both sides
$(x^2 + y^2 - 6y)^2 = (-6 \sqrt{x^2 + y^2})^2$
$x^4 + y^4 + 36y^2 +2x^2y^2 -12y^3 -12x^2y = 36(x^2 + y^2)$
$x^4 + y^4 +36y^2 + 2x^2y^2 -12y^3 -12x^2y = 36x^2 + 36y^2$
$x^4 + y^4 + 36y^2 +2x^2y^2 -12y^3-12x^2y - 36x^2 - 36y^2 = 0$
$x^4 + y^4 -12y^3 + 2x^2y^2 - 12x^2y - 36x^2 = 0$

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4 years ago

Read 2 more answers