Answer:
160 cars
Step-by-step explanation:
The computation of the number of more cars he washed this year is given below;
Last year, he washed 20 cars a week so on yearly basis he washed
= 20 cars × 52 weeks
= 1,040 cars
And, this year he washed 1,200 cars
So, the number of more cars he washed this year is
= 1,200 cars - 1,040 cars
= 160 cars
Answer:
Answer is in the screenshot provided.
Step-by-step explanation:
Work is also in the screenshot provided.
Answer:
The maximum profit is when they make 10 units of A and 2 units of B.
Step-by-step explanation:
Let x is units of milk
Let y units of cacao
Given that :
The company's production plant has a total of 22 units of milk and 46 units of cacao available.
2x + y ≤ 22 (2 unit of milk for each of A and 1 for B; 22 units available)
4x + 3y ≤46 (4 unit of milk for each of A and 3 for B; 46 units available
Graph the constraint equations and find the point of intersection to determine the feasibility region.
The intersection point (algebraically, or from the graph) is (10, 2)
The objective function for the problem is the total profit, which is $6.2 per unit for A and $4.2 per unit for B: 6.2x + 4.2y.
Hence, we substitute (10, 2) into the above function:
6.2*10 + 4.2*2 = 70.4
The maximum profit is when they make 10 units of A and 2 units of B.
Answer:
x = 8/3
Step-by-step explanation:
3x + 16 = 24
3x = 24 - 16 (subtract 16 from both sides)
3x = 8
x = 8/3 (divide both sides by 3)
Answer:
u can't add 2 pictures...so....