All categories

3 years ago

Which best explains why the equation 3x+ 8 = 3x-5 has no solutions?

Mathematics

1 answer:

rusak2 [61]3 years ago

4 0

Answer:

Step-by-step explanation:

The x value is the same on both side of the equation but the other number are not (8≠-5) so the equation can't be true no matter the value plugged for x

You might be interested in

Find the product. (-4·3·2)2 -48 48 -576 576

VLD [36.1K]

(-4*3*2)^2 = (-24)^2 = 576

hope this will help you

5 0

3 years ago

Read 2 more answers

Pencils come in packages of 10.Erasers come in packages of 12. Phillips wants to purpose the smallest number of pencils and eras

balandron [24]

Answer:

The answer to your question is:

Packages of pencils = 6

Packages of erasers = 5

Step-by-step explanation:

Data

Pencils = 10/package

Erasers = 12 / package

Process

Find the least common factor of 10 and 12

10 12 2

5 6 2

5 3 3

5 1 5

LCF = 2 x 2 x 3 x 5 = 60

Finally divide 60 by the number of pencils or erasers in each package

Packages of pencils = 60/10 = 6

Packages of erasers = 60/12 = 5

5 0

3 years ago

Which of the following are solutions to the equation below?

Dovator [93]

Answer:

Apply quaratic equation

6 0

3 years ago

1854times845 could someone help me

vivado [14]

Answer:

1,566,630

Step-by-step explanation:

1854*845=1,566,630

8 0

3 years ago

Write the equation of the line that is the perpendicular bisector of the segment with endpoints (4, 1) and (2, -5)

Sedbober [7]

Answer: $\bold{y=-\dfrac{1}{3}x-1}$

<u>Step-by-step explanation:</u>

(4, 1) & (2, -5)

First, find the slope (m) and then the perpendicular (opposite reciprocal) slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}\\\\\\m=\dfrac{-5-1}{2-4} = \dfrac{-6}{-2}=3\quad \rightarrow \quad m_{\perp}=-\dfrac{1}{3}\\$

Next, find the midpoint of (4, 1) and (2, -5):

$Midpoint=\bigg(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\bigg)\\\\\\.\qquad \qquad=\bigg(\dfrac{4+2}{2},\dfrac{1-5}{2}\bigg)\\\\\\.\qquad \qquad=\bigg(\dfrac{6}{2},\dfrac{-4}{2}\bigg)\\\\\\.\qquad \qquad=(3, -2)$

Lastly, input the perpendicular slope and the midpoint into the Point-Slope formula to find the equation of the line:

$y - y_1 = m_{\perp}(x - x_1)\\\\y - (-2) = -\dfrac{1}{3}(x - 3)\\\\y + 2=-\dfrac{1}{3}x +1\\\\y =-\dfrac{1}{3}x - 1\\$

6 0

3 years ago