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3 years ago

£100 in the ratio 3:2

Mathematics

2 answers:

trasher [3.6K]3 years ago

7 0

Answer:

66.66 (other currency)

Step-by-step explanation:

If every £3 represents 2 of another currency, you just need to figure out how many groups of £3 are in £100 (so £100/£3 = 33.33). Now multiply this value by 2 to get the equivalent of £100 in another currency.

ryzh [129]3 years ago

4 0

If you want to divide something in a 3:2 ratio between two people, just split it in 5 parts.

Then, you assign 2 parts to the first person, and 3 parts to the second. By construction, you're sure that they will have money in a 3:2 ratio, since you literally gave 2 and 3 parts to the two people.

So, just divide 100 by 5 to get the unit amount. Then multiply the unit amount by 2 and 3 to get the split.

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How do you write 54.039

OverLord2011 [107]

Answer:

word form: fifty-four and thirty-nine thousandths.

Step-by-step explanation:

hope it helps

mark me brainliest pls

5 0

3 years ago

Because of safety considerations, in May 2003 the Federal Aviation Administration (FAA) changed its guidelines for how small com

Rasek [7]

Answer:

a) The 95% confidence interval for the mean summer weight (including carry-on luggage) of Frontier Airlines passengers is between 179 and 187 pounds. This means that we are 95% sure that the mean summer weight of all Frontier Airlines passengers is between these two values.

The 95% confidence interval for the mean winter weight (including carry-on luggage) of Frontier Airlines passengers is between 185.4 pounds and 194.6 pounds. This means that we are 95% sure that the mean winter weight of all Frontier Airlines passengers is between these two values.

c) They are respected, as the upper bound of both intervals is below the new FAA recommendations.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve these questions.

Question a:

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 100 - 1 = 99

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 99 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.95}{2} = 0.975$ . So we have T = 1.9842

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 1.9842\frac{20}{\sqrt{100}} = 4$

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 183 - 4 = 179 pounds.

The upper end of the interval is the sample mean added to M. So it is 183 + 4 = 187 pounds.

The 95% confidence interval for the mean summer weight (including carry-on luggage) of Frontier Airlines passengers is between 179 and 187 pounds. This means that we are 95% sure that the mean summer weight of all Frontier Airlines passengers is between these two values.

Question b:

Critical value is the same(same sample size and confidence level).

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 1.9842\frac{23}{\sqrt{100}} = 4.6$

The lower end of the interval is the sample mean subtracted by M. So it is 190 - 4.6 = 185.4 pounds.

The upper end of the interval is the sample mean added to M. So it is 190 + 4.6 = 194.6 pounds.

c. The new FAA recommendations are 190 pounds for summer and 195 pounds for winter. Comment on these recommendations in light of the confidence interval estimates from Parts (a) and (b).

They are respected, as the upper bound of both intervals is below the new FAA recommendations.

7 0

3 years ago

Could Some One Be Kind and Please Answer? :D

nataly862011 [7]

Answer:

Step-by-step explanation:

21.12/0.44=48

I hope this helps :)

Brainliest pls?

4 0

4 years ago