The expected frequency of east campus and passed is C. 42 students
<h3>How to calculate the value?</h3>The table for expected frequency is ,
East Campus West Campus Total
Passed (84*100)/22=42 (84*100)/200 =42 84
Failed (116*100)/200=58 (116*100)/22=58 116
Total 100 100 200
Passed = 84×100/200
= 42
Therefore, the expected frequency of East Campus and Passed is 42 students.
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Given, IJ = 3x + 3, HI = 3x - 1, and HJ = 3x + 8.
Since I is a point on line segment HJ, we can write
Put x=2 in HJ=3x+8.
Therefore, the numerical length of HJ is 14.
Answer:
(a)
(b)
i.
ii.
iii.
Step-by-step explanation:
Given
Solving (a): List all possible elements using set-roster notation.
The possible elements are:
And the number of elements are:
Solving (bi) Exactly 1 girl
From the list of possible elements, we have:
And the number of the list is;
The probability is calculated as;
Solving (bi) At least 2 are girls
From the list of possible elements, we have:
And the number of the list is;
The probability is calculated as;
Solving (biii) No girl
From the list of possible elements, we have:
And the number of the list is;
The probability is calculated as;