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Tanzania [10]
3 years ago
10

What is 1 1/3 x 1/3 in simplest form?

Mathematics
1 answer:
DochEvi [55]3 years ago
4 0

Answer:

4/9

Step-by-step explanation:

1 1/3 * 1/3 =

= (1 + 1/3) * 1/3

= (3/3 + 1/3) * 1/3

= 4/3 * 1/3

= 4/9

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The student council is hosting a drawing to raise money for scholarships. They are selling tickets for $8 each and will sell 900
andrew-mc [135]

Step-by-step explanation:

the probability that the ticket will win you 600 dollars * 1/1500 = 600/1500.

the probability that the ticket will win you 50 dollars is 50 * 5/1500 = 250/1500.

the probability that the ticket will win you 25 dollars is 25 * 20/1500 = 500/1500.

your expected value is -1 + 600/1500 + 250/1500 + 500/1500 = -.1.

the average loss for each dollar that is bet is equal to 10 cents.

hope this helped

7 0
3 years ago
Evaluate ((6+2) ÷ (10-8) +10) ∙ 5
miskamm [114]
You can do that on photo math
5 0
3 years ago
Lindsay has some yellow and red flowers in a vase. The ratio of yellow to red flowers is 4 : 7. The number of yellow flowers in
Naddik [55]
14 red flowers so d because it says 4:7 so there is 8 yellow and 14 red so so fine the lowest common multiple thin divide both by same LCM and git your answer <span />
3 0
3 years ago
Read 2 more answers
To get the ratio of three green marbles and six blue marbles will there be in simplest form?
katen-ka-za [31]

Answer:

Well your question is a little unclear but say there is a bag of marbles containing 3 green marbles and 6 blue marbles then if you wanted to find the ratio of the green marbles it would be 3/9 or 1/3

8 0
2 years ago
Read 2 more answers
1.What are the zeros of the polynomial function?
Lorico [155]
Let's to the first example:

f(x) = x^2 + 9x + 20

Ussing the formula of basckara

a = 1
b = 9
c = 20

Delta = b^2 - 4ac

Delta = 9^2 - 4.(1).(20)

Delta = 81 - 80

Delta = 1

x = [ -b +/- √(Delta) ]/2a

Replacing the data:

x = [ -9 +/- √1 ]/2

x' = (-9 -1)/2 <=> - 5

Or

x" = (-9+1)/2 <=> - 4
_______________

Already the second example:

f(x) = x^2 -4x -60

Ussing the formula of basckara again

a = 1
b = -4
c = -60

Delta = b^2 -4ac

Delta = (-4)^2 -4.(1).(-60)

Delta = 16 + 240

Delta = 256

Then, following:

x = [ -b +/- √(Delta)]/2a

Replacing the information

x = [ -(-4) +/- √256 ]/2

x = [ 4 +/- 16]/2

x' = (4-16)/2 <=> -6

Or

x" = (4+16)/2 <=> 10
______________

Now we are going to the 3 example

x^2 + 24 = 14x

Isolating 14x , but changing the sinal positive to negative

x^2 - 14x + 24 = 0

Now we can to apply the formula of basckara

a = 1
b = -14
c = 24

Delta = b^2 -4ac

Delta = (-14)^2 -4.(1).(24)

Delta = 196 - 96

Delta = 100

Then we stayed with:

x = [ -b +/- √Delta ]/2a

x = [ -(-14) +/- √100 ]/2

We wiil have two possibilities

x' = ( 14 -10)/2 <=> 2

Or

x" = (14 +10)/2 <=> 12
________________


To the last example will be the same thing.

f(x) = x^2 - x -72

a = 1
b = -1
c = -72

Delta = b^2 -4ac

Delta = (-1)^2 -4(1).(-72)

Delta = 1 + 288

Delta = 289

Then we are going to stay:

x = [ -b +/- √Delta]/2a

x = [ -(-1) +/- √289]/2

x = ( 1 +/- 17)/2

We will have two roots

That's :

x = (1 - 17)/2 <=> -8

Or

x = (1+17)/2 <=> 9


Well, this would be your answers.


7 0
3 years ago
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