<span>4. Simplify the expression.
sine of x to the second power minus one divided by cosine of negative x</span>
<span>(1−sin2(x))/(sin(x)−csc(x))<span>
</span>sin2x+cos2x=1</span>
<span>1−sin2x=cos2x<span>
</span>cos2(x)/(sin(x)−csc(x))</span>
<span>csc(x)=1/sin(x)</span>
<span>cos2(x)/(sin(x)− 1/sin(x))= cos2(x)/((sin2(x)− 1)/sin(x))</span>
<span>sin2(x)− 1=-cos2(x)</span>
<span>cos2(x)/(( -cos2(x))/sin(x))
=-sin(x)</span>
<span>
the answer is the letter a)
-sin x
</span><span>
5. Find all solutions in the interval [0, 2π). (6 points)sin2x + sin x = 0</span> using a graphical tool
the solutions
x1=0
x2=pi
<span>x3=3pi/2
the answer is the letter </span><span>
D) x = 0, π, three pi divided by two</span>
Answer:
$43.66 rounded to the nearest 10 =$40
15% of $40 = $6
Step-by-step explanation:
So here we use the pythagorean theorem which is a2 + b2 = c2 (“a” squared times “b” squared equals “c” squared) the length from calvins house to the intersection is “a” and the length from phoebes house to the intersection is “b” so in order to find out the length of “c” (calvins house to phoebes house) we need to use the pythagorean theorem
a2 275x275=75,625
b2 113x113 = 12,769
so now that we have figured out what a2 and b2 are let’s add them
75,625 + 12,769 = 88,394
now since we only need to find out the length and not the area we need to find the square root of 88,394
the square root of 88,394 is 297.311 (i cut off the decimal after three places)
the direct length from phoebes house to calvins is 297.311 meters
Answer:
21.5
Step-by-step explanation:
→_→
It did not say if if it was a acute triangle or a obtuse triangle
