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Rom4ik [11]
3 years ago
12

What is the least common denominator of 2/9 and 2/3

Mathematics
1 answer:
julsineya [31]3 years ago
3 0

Answer:

2\9=1

2\3=1

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
Multiply
Dmitriy789 [7]

Answer:

The product of given two fractions is

\frac{4(x+2)}{(x-1)(x+3)}

Therefore \frac{2(2+3)}{x(x-1)}\times \frac{4x(x+2)}{10(x+3)}=\frac{4(x+2)}{(x-1)(x+3)}

Step-by-step explanation:

Given expression is  

\frac{2(2+3)}{x(x-1)}\times \frac{4x(x+2)}{10(x+3)}

To find the product of two given fractions as below :

\frac{2(2+3)}{x(x-1)}\times \frac{4x(x+2)}{10(x+3)}=\frac{2(5)}{x(x-1)}\times \frac{2x(x+2)}{5(x+3)}

=\frac{10}{x(x-1)}\times \frac{2x(x+2)}{5(x+3)}

=\frac{20x(x+2)}{5x(x-1)(x+3)}

=\frac{20x^2+40x}{(5x^2-5x)(x+3)} (multiply each term in the factor to each term in the another factor )

=\frac{20x^2+40x}{5x^3+15x^2-5x^2-15x}  ( adding the like terms )

=\frac{20x^2+40x}{5x^3+10x^2-15x}

=\frac{5x(4x+8)}{5x(x^2+2x-3)}

=\frac{4(x+2)}{(x-1)(x+3)}

Therefore \frac{2(2+3)}{x(x-1)}\times \frac{4x(x+2)}{10(x+3)}=\frac{4(x+2)}{(x-1)(x+3)}

Therefore the product of given two fractions is \frac{4(x+2)}{(x-1)(x+3)}

6 0
3 years ago
What are the solutions to the quadratic equation 4x^2-9x-9=0?
gavmur [86]
X = 3, -
 \frac{3}{4}
4 0
3 years ago
Read 2 more answers
Please help.
aev [14]
D account history is the answer
4 0
3 years ago
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Surface area of the pyramid
koban [17]

Answer:

the answer is 71.2

Step-by-step explanation:

4×4=16

6.9×2=13.8

13.8×4=55.2

55.2+16=71.2

5 0
3 years ago
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