The given information permits us to calculate the circumference (C) of the wheel as follows
Then (as you said correctly!) the same wheel will move
after 16 rolls.
Answer:
Side lengths of 12,8,8
Step-by-step explanation:
In an isosceles triangle the base is different from the other 2 sides which are the same so
28=12+2x (x being the side of the repeat sides)
14=6+x (divide both sides by 2)
8=x (subtract 6 from both sides) so
Side lengths of 12,8,8
with what? you need to explain whats going on in order to get the help you need!
Answer: Hello there!
this type of equations in one dimension (when all the factors are constants) are written as:
h = initial position + initial velocity*t + (acceleration/2)*t^2
First, let's describe the hunter's equation:
We know that Graham moves with a velocity of 1.5 ft/s, and when he is 18 ft above the ground, Hunter throws the ball, and because Graham is pulled with a cable, he is not affected by gravity.
If we define t= 0 when Graham is 18 ft above the ground, the equation for Graham height (in feet) is:
h = 18 + 1.5t
where t in seconds.
Now, the equation for the ball:
We know that at t= 0, the ball is thrown from an initial distance of 5ft, with an initial velocity of 24ft/s and is affected by gravity acceleration g, where g is equal to: 32.2 ft/s (notice that the gravity pulls the ball downwards, so it will have a negative sign)
the equation for the ball is:
h = 5 + 24t - (32.2/2)t^2 = 5 + 24t - 16.1t^2
So the system is:
h = 18 + 1.5t
h = 5 +24t - 16.1t^2
so the right answer is A
We plug in 14 for x when we set the two equations equal to each other to prove they are equal.
So true LM congruent to MN
