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marissa [1.9K]
4 years ago
7

The frequency table below shows the hourly wages of 22 factory workers. How many are paid $10.50 per hour or more?

Mathematics
1 answer:
Ostrovityanka [42]4 years ago
5 0
The answer would be 11. Hope this helps :)
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An inverse variation includes the points (15,1) and (n,5). Find n
djyliett [7]
Inverse variation: y=k/x

1. plug in the values: (15,1)
1=k/15

2. solve for k

3. Now, plug in what you can for the second point: (n,5)
5=k/n (if you do the step above, you will know “k”.

4. Solve for “n”


7 0
2 years ago
Leon read 5/7 of the pages in his book.He has 28 pages left to read.How many pages has he read already?
Fittoniya [83]
You would first divide 28 by 7.
28 / 7 = 4.
Now multiply 4 by 5.
4 X 5 = 20.

Therefore, Leon read 20 pages.
4 0
3 years ago
Use the rule n ÷ 4, where n represents the position of a term in a sequence. Find the first four terms in the sequence.
Ne4ueva [31]

Answer:

a1 = 1/4

a2 = 1/2

a3 = 3/4

a4 = 1

Step-by-step explanation:

an = a/n

then when a= 1, 2, 3, 4

a1 = 1/4

a2 = 2/4 = 1/2

a3 = 3/4

a4 = 4/4 = 1

8 0
3 years ago
The diagonals of a rumbus are 21m and 32m what is area of the rombus
Liula [17]
Consider this option:
1. formula is: S=0.5*d₁*d₂, where d₁;d₂ - the diagonals of the rhombus.
2. substituting the values into the formula: S=0.5*21*32=336 m².

answer: 336 m².
5 0
3 years ago
Read 2 more answers
Section J in an arena has 20 rows each row has 15 seats all tickets cost $18 each if all the seats are sold, how much money will
quester [9]
If there are 20 rows each and 15 per row then you would multiply 20(15) = 300 then so there are 300 seats in Section J. each seat is 18$ so you would multiply 300(18) = 5400  so section J would get 5,400$ if it were to be sold out. The equation is 20(15)=300(18)=5400
5 0
3 years ago
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