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3 years ago

What is the fifth term in the expansion of (3x - 3y)7?

Mathematics

1 answer:

Ksenya-84 [330]3 years ago

4 0

5th term of 3x-3y)7 is 7c4

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if a rectangles height was 11.1 in tall and the width was 11.7 in wide what is the width if the height is reduced to 3.7 in

kkurt [141]

Your answer is (in my opinion): 11.7in wide.
Just becuse the hight changed it does NOT mean that the width changed.

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3 years ago

Use the formula to factor n8 – 9

gulaghasi [49]

Hi!

The correct answer is ( $n^{4}$ +3)( $n^{4}$ -3)

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4 years ago

Can you help thank you ???????

Dmitry_Shevchenko [17]

Answer:

L = 186

Step-by-step explanation:

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3 years ago

Read 2 more answers

Please help answer thisq

Julli [10]

Answer:

More than one independent variable being tested.

Step-by-step explanation:

If a student wants to figure out if ONLY salt affects the growth of seeds, the student shouldn't change the amount of sunlight being received.

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3 years ago

Enter a recursive rule for the geometric sequence. 6, −18, 54, −162, ...

svlad2 [7]

Answer:

The required recursive formula is:

$a_n=(-3)\times a_{n-1}$

Step-by-step explanation:

We are given a geometric sequence as:

6,-18,54,-162,.....

Clearly after looking at different terms of the sequence we could observe that the sequence is an geometric progression (G.P.) with common ratio= -3 denoted by r.

Let $a_n$ represents the nth term of the sequence.

This means that:

$a_1=6, a_2=-18, a_3=54, a_4=-162,......$

As the common ratio is -3.

so,

$a_1=6\\\\a_2=-18=(-3)\times a_1\\\\a_3=54=(-3)\times a_2\\\\.\\.\\.\\.\\.\\.\\.\\.\\.a_n=(-3)\times a_{n-1}$

Hence, the required recursive formula for the geometric sequence is:

$a_n=(-3)\times a_{n-1}$

5 0

3 years ago