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Helen [10]
3 years ago
11

What is the fifth term in the expansion of (3x - 3y)7?

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
4 0
5th term of 3x-3y)7 is 7c4
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Given the equation -4x+3y=-17 find the value of y if the ordered pair (2,y) is a solution
Alex17521 [72]

Answer:

-3

Step-by-step explanation:

First - change the equation to y=mx+b format

3y/3 = 4x/3 - 17/3

y = 4/3x - 17/3

Second - then (2,y) plug x = 2

Third - solve

y = 4/3(2) - 17/3

y = 8/3 - 17/3 = -9/3 = -3

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3 years ago
PLEASE HELP ME THANKS IF u do
garik1379 [7]

Answer:

The third one

Step-by-step explanation:

It can't be the first one since the peak is 4 since it is the highest

It can't be the second one because the data is all different

It could be the third one since their are gaps

And It can't be the fourth one because the range is 7

So it must be the third one

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3 years ago
How many minutes have elapsed between 7:22 pm and 7:36 pm?
Nutka1998 [239]
The hour has stayed the same. 36-22 is 14. That's 14 minutes between.
4 0
3 years ago
A container holds 23 gallon of apple juice. If four people from the cross-country track team share the juice equally, how much j
Kruka [31]

Answer:5.75

Step-by-step explanation:

7 0
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Read 2 more answers
Find the domain and range of<br><br> f(x)= (2x+6) / ((x^2)-x-12)
creativ13 [48]

Answer:

Step-by-step explanation:

If you want to determine the domain and range of this analytically, you first need to factor the numerator and denominator to see if there is a common factor that can be reduced away.  If there is, this affects the domain.  The domain are the values in the denominator that the function covers as far as the x-values go.  If we factor both the numerator and denominator, we get this:

f(x)=\frac{2(x+3)}{(x-4)(x+3)}

Since there is a common factor in the numerator and the denominator, (x + 3), we can reduce those away.  That type of discontinuity is called a removeable discontinuity and creates a hole in the graph at that value of x.  The other factor, (x - 4), does not cancel out.  This is called a vertical asymptote and affects the domain of the function.  Since the denominator of a rational function (or any fraction, for that matter!) can't EVER equal 0, we see that the denominator of this function goes to 0 where x = 4.  That means that the function has to split at that x-value.  It comes in from the left, from negative infinity and goes down to negative infinity at x = 4.  Then the graph picks up again to the right of x = 4 and comes from positive infinity and goes to positive infinity.  The domain is:

(-∞, 4) U (4, ∞)

The range is (-∞, ∞)

If you're having trouble following the wording, refer to the graph of the function on your calculator and it should become apparent.

8 0
3 years ago
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