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3 years ago

What is the fifth term in the expansion of (3x - 3y)7?

Mathematics

1 answer:

Ksenya-84 [330]3 years ago

4 0

5th term of 3x-3y)7 is 7c4

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A farmer randomly inspected 16 of his 93 peach trees for signs of disease. Two of those trees showed signs of disease. Find .

Dmitriy789 [7]

<span>I think you wanted to find p̂, or "p-hat". This is simply the proportion of the sample. So:

p̂ = 16/93 ~= 0.172

Hope this helps :)</span>

4 0

3 years ago

Read 2 more answers

Factorize x^2/16+xy+4y^2

lisov135 [29]

Answer:

$\frac{x^2}{16} +xy+4y^2$ can be factored out as: $(\frac{x}{4} +2\,y)^2$

Step-by-step explanation:

Recall the formula for the perfect square of a binomial :

$(a+b)^2=a^2+2ab+b^2$

Now, let's try to identify the values of $a$ and $b$ in the given trinomial.

Notice that the first term and the last term are perfect squares:

$\frac{x^2}{16} = (\frac{x}{4} )^2\\4y^2=(2y)^2$

so, we can investigate what the middle term would be considering our $a=\frac{x}{4}$ , and $b=2y$ :

$2\,a\,b=2\,(\frac{x}{4}) \,(2\,y)=x\,y$

Therefore, the calculated middle term agrees with the given middle term, so we can conclude that this trinomial is the perfect square of the binomial:

$(\frac{x}{4} +2\,y)^2$

4 0

3 years ago

Hayden decided to take martial arts classes at his local gym. He pays $35 each month for his membership and $12 for every class

gizmo_the_mogwai [7]

Hayden had the membership for one month and took 6 classes.

8 0

3 years ago

Find the coordinates of the other endpoint of the segment, given its midpoint and one endpoint. (Hint: Let (x,y) be the unkno

spin [16.1K]

The other endpoint is (1, -17).

The midpoint formula is:

$m=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$

Using our midpoint and endpoint, we have:
$(6, -11) = (\frac{11+x_2}{2}, \frac{-5+y_2}{2})
\\
\\6=\frac{11+x_2}{2} \text{ and } -11=\frac{-5+y_2}{2}
$

For the first equation (to find the x-coordinate) we will multiply both sides by 2:
$6\times2=\frac{11+x_2}{2}\times 2
\\
\\12=11+x_2$

Subtract 11 from both sides:
12 - 11 = 11+x₂ - 11
1 = x₂

For the second equation (the y-coordinate) we multiply both sides by 2:
$-11\times2=\frac{-5+y_2}{2}\times 2
\\
\\-22=-5+y_2$

Add 5 to both sides:
-22+5 = -5+y₂ + 5
-17 = y₂

This means that (x₂, y₂) is at (1, -17).

4 0

3 years ago

Write each equation in slope-intercept form of the equation of a line. Underline the slope and circle the y-intercept in each eq

Alik [6]

Answer:

see below:

Step-by-step explanation:

2y–6=0

a. slope intercept form using y = mx + b

y = 6/2

y = 3

b. slope: use the slope intercept form: y = mx + b

slope = m = 0

c. y-intercept = (0,3)

7 0

3 years ago