The quadratic formula is 
.
From the problem, a is 1, b is -1, and c is 12. Plugging in these values gives:
Because there is a square root of a negative number, there is no solution.
Steps
I’m using elimination so I’m trying to get rid of y
To do that I multiply the first equation by 2 and the second by -3. Then solve
4x + 6x = 12
15x + -6x = -12
—————————
19x + 0 = 0
Divid by 19 to get x to one side. 0/19 is 0 so
X= 0
Plug that into an equation so 0 + 3y = 6
Divid by 3 and y = 2
Answer x = 0 y = 2
Answer:
70%
Step-by-step explanation:
I'm sorry but I don't really know how to explain it other than 70% of 30 is 21 so that means that 30% of the students turned their essay in on time.
(sorry for not being able to explain it but I hope it helped)
Answer:
B
Step-by-step explanation:
3 rectangles are 3 x 7 x 2 = 42
2 triangles are 2 x 1/2 x 2 x 
= 2
note that you have to use Pythagoras Theorem to solve for the height of the triangle
y - y₁ = m(x - x₁)
y - (-1) = 4[x - (-3)]
y + 1 = 4(x + 3)
y + 1 = 4(x) + 4(3)
y + 1 = 4x + 12
- 1 - 1
y = 4x + 11
The answer is B.
