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vova2212 [387]
3 years ago
14

How do you find the sine and tangent of an angle if you are given the cosine?

Mathematics
1 answer:
Anni [7]3 years ago
6 0

Answer:

  • sin = √(1 -cos²)
  • tan = (√(1 -cos²))/cos

Step-by-step explanation:

\displaystyle\sin^2{\theta}+\cos^2{\theta}=1 \qquad\text{Pythagorean identiy}\\\\\sin{\theta}=\sqrt{1-\cos^2{\theta}} \qquad\text{solved for sine}\\\\\tan{\theta}=\frac{\sin{\theta}}{\cos{\theta}}=\frac{\sqrt{1-\cos^2{\theta}}}{\cos{\theta}}

_____

If you draw a triangle with a hypotenuse of 1 and an "adjacent" leg of "cos", then using the Pythagorean theorem, you can see that the "opposite" leg will be √(1-cos²) and the tangent will be (√(1-cos²))/cos. Whether or not you're allowed to draw such a triangle on paper, you can certainly do it in your mind.

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A circle of yellow tulips is planted in Cedarburg's central park. Pam measured the circle and calculated that is has a circumfer
lozanna [386]

Answer:

The circle's diameter is 4\ yd

Step-by-step explanation:

we know that

The circumference of a circle is equal to

C=\pi D

where

D is the diameter of the circle

In this problem we have

C=12.56\ yd

\pi=3.14

substitute the values and solve for D

12.56=(3.14)D

D=12.56/(3.14)=4\ yd

6 0
3 years ago
Which of the following is not a property of a chi-square distribution?
laiz [17]

Answer:

c) Is not a property (hence (d) is not either)

Step-by-step explanation:

Remember that the chi square distribution with k degrees of freedom has this formula

\chi_k^2 = \matchal{N}_1^2 +  \matchal{N}_2^2 + ... + \, \matchal{N}_{k-1}^2 +  \matchal{N}_k^2

Where N₁ , N₂m .... N_k are independent random variables with standard normal distribution. Since it is a sum of squares, then the chi square distribution cant take negative values, thus (c) is not true as property. Therefore, (d) cant be true either.

Since the chi square is a sum of squares of a symmetrical random variable, it is skewed to the right (values with big absolute value, either positive or negative, will represent a big weight for the graph that is not compensated with values near 0). This shows that (a) is true

The more degrees of freedom the chi square has, the less skewed to the right it is, up to the point of being almost symmetrical for high values of k. In fact, the Central Limit Theorem states that a chi sqare with n degrees of freedom, with n big, will have a distribution approximate to a Normal distribution, therefore, it is not very skewed for high values of n. As a conclusion, the shape of the distribution changes when the degrees of freedom increase, because the distribution is more symmetrical the higher the degrees of freedom are. Thus, (b) is true.

6 0
3 years ago
. The ratio of three angles of a triangle is 1:2:3. Find the measurement of<br>the angles.​
nydimaria [60]

Answer:

Step-by-step explanation:

Sum of angles in a Δ= 180°

x + 2x +3x = 180

6x= 180

Divide both sides by 6

x=30

sooo x= 1×30= 30,   2x= 2×30= 60,   3x=3×30= 90

since 30+60+90= 180

∴the angles are 30°,60° and 90° respectively

5 0
3 years ago
Figure ABCDE was reflected across the line y=x to create figure A’B’C’D’E’.What are the coordinates of the pre-image of E’?
Minchanka [31]

Answer:

the answer is -2,6

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What number is a common factor of 16 and 56
igomit [66]

Answer:

8

Step-by-step explanation:

8 x 2 = 16

8 x 7 = 56

Can I get brainliest

8 0
3 years ago
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