The rate of change will be given by:
v(h)=3√h=3h^0.5
The rate of change will be:
v'(h)=(3×0.5)x^-0.5=1.5x^-0.5
hence when h=2 meters, then the rate of change will be:
v'(h)=1.5×2^-0.5
v'(h)=1.061 m/s
Answer:
Area of trapezoid = 67.6 square units
Step-by-step explanation:
Area of a trapezoid is given by the expression,
Area of the trapezoid = 
Here,
and
are the parallel sides of the given trapezoid.
And '
' = Height between the parallel sides
From the given triangle ABE,
m(∠ABE) = m(∠ABC) - m(∠EBC)
m(∠ABE) = 120° - 90°
= 30°
By applying cosine rule in the given triangle,
cos(30°) = 


BE =
units
By applying sine rule in ΔABE,
sin(30°) = 


AE = 3 units
Length of 
Length of
[AE = FD, since given trapezoid ABCD is an isosceles trapezoid]


Height between the parallel sides 
Area of the trapezoid = 
= 
= 
= 67.6 square units
Answer:to determine if a solution is extraneous, we simply plug the solution into the original equation.
Step-by-step explanation:
hope this helps!
Answer:
I believe it's 1.864114 miles.
23°F
Step-by-step explanation:
f=1.8c+32
f=1.8×-5 +32
= -9 +32
=23°F.