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3 years ago

6

What is the reminder when (3x^3-2x^2+4x-3) is divided by (x^2+3x+3)

1 answer:

NARA [144]3 years ago

5 0

(For full answer you might have to go to the comments)

Answer: 28x+30

Explanation: we divide (3x^3-2x^2+4x-3) by (x^2+3x+3) Using long division
3x-11
___________________
(x^2+3x+3) 3x^3-2x^2+4x-3

-(3x^3+9x^2+9x)
__________________

-11x^2-5x-3

-(-11x^2-33x-33)
____________
28x+30

So our remainder will be 28x+30

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2 years ago

Determine the value of variables a, b, and c that make each equation true.

dybincka [34]

Corrected Question

Determine the values of a, b and c that make each equation true.

$(x^a)^6=\dfrac{1}{x^{30}} \\\\(x^{-7})^{-4}=x^b\\\\(x^{-2})^c=x^{22}$

Answer:

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Step-by-step explanation:

To solve for a,b and c, we apply the following laws of indices

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