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ozzi
3 years ago
6

What is the reminder when (3x^3-2x^2+4x-3) is divided by (x^2+3x+3)

Mathematics
1 answer:
NARA [144]3 years ago
5 0
(For full answer you might have to go to the comments)

Answer: 28x+30

Explanation: we divide (3x^3-2x^2+4x-3) by (x^2+3x+3) Using long division
3x-11
___________________
(x^2+3x+3) 3x^3-2x^2+4x-3


-(3x^3+9x^2+9x)
__________________

-11x^2-5x-3

-(-11x^2-33x-33)
____________
28x+30

So our remainder will be 28x+30
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