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3 years ago

CAN SOMEONE PLEASE HELP ME WITH MY MATH ASAP PLEASE!!!!

Mathematics

1 answer:

Ivanshal [37]3 years ago

8 0

Answer:

Step-by-step explanation:

Hello,

The two triangles are similar and x is positive, different from 0, so we can write.

$\dfrac{x}{9}=\dfrac{12}{x}\\\\x^2=12\times 9\\\\ x = \sqrt{4\times 3 \times 9}=2\times 3 \times \sqrt{3}\\\\ \boxed{\sf \bf x=6\sqrt{3} }$

Thanks

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3 years ago

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Answer:

Step-by-step explanation:

$\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\frac{0}{0} \\\\we\ can \ use\ Hospital's\ Rule\\\\\\f(x)=\sqrt{2x}-\sqrt{3x-a} \qquad f'(x)=\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} \\\\g(x)=\sqrt{x} -\sqrt{a} \qquad g'(x)=\dfrac{1}{2\sqrt{x}} \\\\\\\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\lim_{n \to a} \dfrac{\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} }{\dfrac{1}{2\sqrt{x}} }\\\\$

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2 years ago

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Answer:

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2 years ago

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2 years ago

Read 2 more answers

Help!!!!¡¡¡¡ i need help solving this it will increase my letter grade!!!!

Shtirlitz [24]

Answer:

The answer is below⬇️⬇️

Step-by-step explanation:

f(x) = 3x+4

g(x) = 2x

h(x) = x²+x-2

g(hx) = 2(x²+x-2)

= 2x²+2x-4

f(g(hx))=3(2x²+2x-4)+4

=6x²+6x-12+4

=6x²+6x-8

g(f(g(hx)))=2(6x²+6x-8)

=12x²+12x-16

f(g(f(g(hx))))=3(12x²+12x-16)+4

=36x²+36x-48+4

=36x²+36x-44

h(f(g(f(g(hx)))))=(36x²+36x-44)²+36x²+36x-44-2

=1296x⁴+2592x³-1872x²-3168x+1936+36x²+36x-46

=1296x⁴+2592x³-1836x²-3132x+1890

f(h(f(g(f(g(hx))))))=3(1296x⁴+2592x³-1836x²-3132x+1890)+4

=3888x⁴+7776x³-5508x²-9396x+5674

h(f(h(f(g(f(g(hx)))))))=(3888x⁴+7776x³-5508x²-9396x+5674)²+3888x⁴+7776x³-5508x²-9396x+5674-2

=15116544x⁸+60466176x⁷+17635968x⁶-158723712x⁵-71663616x⁴+657591048x³-255531048x²-106635204x+32194276

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3 years ago

CAN SOMEONE PLEASE HELP ME WITH MY MATH ASAP PLEASE!!!!​

CAN SOMEONE PLEASE HELP ME WITH MY MATH ASAP PLEASE!!!!