Well I don't know.
Let's think about it:
-- There are 6 possibilities for each role.
So 36 possibilities for 2 rolls.
Doesn't take us anywhere.
New direction:
-- If the first roll is odd, then you need another odd on the second one.
-- If the first roll is even, then you need another even on the second one.
This may be the key, right here !
-- The die has 3 odds and 3 evens.
-- Probability of an odd followed by another odd = (1/2) x (1/2) = 1/4
-- Probability of an even followed by another even = (1/2) x (1/2) = 1/4
I'm sure this is it. I'm a little shaky on how to combine those 2 probs.
Ah hah !
Try this:
Probability of either 1 sequence or the other one is (1/4) + (1/4) = 1/2 .
That means ... Regardless of what the first roll is, the probability of
the second roll matching it in oddness or evenness is 1/2 .
So the probability of 2 rolls that sum to an even number is 1/2 = 50% .
Is this reasonable, or sleazy ?
Hello,
You have just to read the arrows un reversed order:
in f we find (-1,-3) so in f^{-1} we find (-1,-3)^{-1}=(-3,-1)
Step-by-step explanation:
Since AD bisects BC,
BD = DC.
Therefore 5x - 10 = 3x + 10 and x = 10.
Area of the 2 end triangles plus area of the 2 rectangular sides plus the area of the bottom rectangle
2 end Triangles
=2x(1/2bh)
=2x1/2x4x6
=24
2 side rectangles
=2(lw)
=2x5x13
=130
Bottom rectangle
=6x13
=78
Total = 24 + 130 + 78 =232
If the question is what I think it is, then it's simple. All you need to do is divide 420 by 15; and you'll get the answer: 28.
