Answer:
We use Baye's theorem: P(A)P(B|A) = P(B)P(A|B)
with (A) being defective and
(B) marked as defective
we have to find P(B) = P(A).P(B|A) + P(¬A)P(B|¬A). .......eq(2)
Since P(A) = 0.1 and P(B|A)=0.9,
P(¬A) = 1 - P(A) = 1 - 0.1 = 0.9
and
P(B|A¬) = 1 - P(¬B|¬A) = 1 - 0.85 = 0.15
put these values in eq(2)
P(B) = (0.1 × 0.9) + (0.9 × 0.15)
= 0.225 put this in eq(1) and solve for P(B)
P(B) = 0.4
Answer:
First image: (6, -1)
2nd image: y = 63
Explanation:
1)
2x + y = 11
1/2x - 5y = 8
y = -2x + 11
1/2x - 5(-2x + 11) = 8
1/2x + 10x - 55 = 8
10.5x - 55 = 8
10.5x = 63
x = 6
2x + y = 11
2(6) + y = 11
12 + y = 11
y = -1
(x , y) = (6, -1)
2)
1/4(8y - 4.8) = 2 (0.9y + 5.4) + 3/5
2y - 1.2 = 1.8y + 10.8 + 0.6
0.2y - 1.2 = 11.4
0.2y = 12.6
y = 63
178-35=143
143/5= 28.6
he paid $28.6 every month
Answer:
Step-by-step explanation:
Add 234 and 8.
234+8= 242
Subract 55 from 242.
242-55=187.
H+20=35-4H
first, combine your like terms, which are the Hs
add the 4H to both sides, and you will get
5H+20=35
now subtract 20 from both sides, that will cancel out the 20 on the left and leave you with
5H=15
finally, divide both sides by 5 and you will get H=3.
