2 years ago

The quotient of k and 9 is greater than 1/3

Mathematics

1 answer:

vagabundo [1.1K]2 years ago

6 0

K/9 > 1/3
i believe this is how it is represented.

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Find the Inverse y = x+10/7

Alona [7]

Answer:

x - $\frac{10}{7}$

Step-by-step explanation:

y = x + 10/7

x = y + 10/7

x - 10/7 = y

y = x - 10/7

x - $\frac{10}{7}$

3 0

3 years ago

cho phương trình 2x^2-5x-9 có hai nghiệm là x1,x2. không giải phương trình, hãy tính giá trị của biểu thức A= x1^2+x2^2-2x1x2^2

irga5000 [103]

Step-by-step explanation:

please subscribe to my mom channel please

https://youtu.be/f_kgUUaMZlw

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2 years ago

You and your friend mix water and citric acid. You add 3 cups of citric acid for every 16 cups of water. Your friend adds 2 cups

Viktor [21]

Answer:

You:If it’s was 6 cups of citric I’d be to 32 water

Your friend: if it was 4 cups it’d be 12 water

Step-by-step explanation:

I believe your friends is more acidic because your Is being diluted more

4 0

2 years ago

The volume of a single layer in a rectangular prism is 18 cubic centimeters. There are 5 layers in this rectangular prism. What

sweet [91]

Answer: $90cm^3$

Step-by-step explanation:

A rectangular prism is a three-dimensional solid.

A rectangular prism has six faces (each one of these faces are rectangles), eight vertices and twelve edges.

You know that this rectangular prism has 5 layers and the volume of one of these layers is 18 cubic centimeters ( $18cm^3$ ).

Assuming that all these layers are equal, the volume of this rectangular prism can be calculated with:

$V_{prism}=5*V_1$

Where $V_1$ is the volume of one layer.

Substituting, you get:

$V_{prism}=(5)(18cm^3)\\\\V_{prism}=90cm^3$

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3 years ago

Determine the missing side lengths

svetlana [45]

Answer:

Given that is a 45-45 triangle, the hypotenuse should be x $\sqrt{2}$ , so in this case. The hypotenuse should be 3 $\sqrt{2}$ , and the other side lengths 3. I see no other way of it going other than that one; I hope I helped at least a bit!

Step-by-step explanation:

6 0

3 years ago

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