Answer:
<h3>
A = 0.5(2x+6)(6x+13) = 6x² + 49x + 78</h3>
Step-by-step explanation:
H = 2x+6 - the hight
3H = 3(2x+6) - triple the hight
3H-5 = 3(2x+6) - 5 - five less than triple the height
Area of triangle: A = 0.5BH
B = 3(2x+6)-5 = 6x + 18 - 5 = 6x + 13
H = 2x+6
So:
A = 0.5(2x+6)(6x+13) = (x+6)(6x+13) = 6x² + 13x + 36x + 78
A = 6x² + 49x + 78
Answer:
a) not proportional
b) proportional; k = 
Step-by-step explanation:
a) for any proportional equation, the line must pass through the origin. The equation in a) is y = 4x + 1, and the '+1' is the y-intercept. This means that the line does not pass through the origin, so x and y cannot increase by the same amount (i.e. they are not proportional).
Another way to determine this is is to use the y = kx base. If you have an equation that fits that it's likely proportional.
Here, if the equation was only y = 4x then it'd be proportional because u can see that k = 4. This is not the equation though, and the 4x + 1 doesn't fit to the y = kx formula so it can't be proportional.
b) straight away you can see that there's no 'c' term (y = mx + c) which means the y-intercept is 0, so the line passes through the origin. While this does not immediately mean the line is proportional, you can make sure that it is by checking it fits with the y = kx equation.
y = -(3/5)x fits with y = kx, with k being -3/5
The coefficient is the number . so if the problem said 16x the coefficient would be 16 . the answer is 14
Answer:
In a rhombus, the diagonals bisect at right angles. That means half the diagonals form a right angle triangle then we can try the Pythagorean theorem. so -
one side of triangle = 6/2 =3 (half of the diagonal)
other side = 8/2 = 4
a^2 + b^2 = c2
3 ^2 + 4^2 = c^2
9+16 = c^2
c^2=25
c =
= 5
the hypothenus forms one side of the rhombus and here the hypothenus is 5, so the lenght of a side is 5 !
nice
i think there's supposed to be more to the problem lol