How do I compare and order the following numbers 5.2, -5.6 repeating, 3 9/10, and the square root of 21?
1 answer:
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Answer:
Step-by-step explanation:
1)First convert mixed fraction to improper fraction and them prime factorize
2)
3) 0.00706 = 7.06 *
<em>4)</em> 144 = 12 * 12
12 = 6*2
6 = 2*3
Prime factorization of 144 = 2 * 3 * 2 * 2 * 3 *2
= 2⁴ * 3²
5) To find LCM, prime factorize 96 & 144
96 = 2 * 2 * 2 * 2 * 2 * 3 = 2⁵ * 3
144 = 2⁴ * 3²
LCM = 2⁵ * 3² = 32 * 9 = 288
6) HCF
105 = 7 * 5 * 3
135 = 5 * 3* 3 * 3
180 = 5 * 3 * 3 * 2 * 2
HCF = 5 * 3 = 15
7) 24 = 3 * 2 * 2 * 2 = 3 * 2³
36 = 3 * 3 * 2 * 2 = 3² * 2²
40 = 5 * 2 * 2 * 2 = 5 * 2³
LCM = 5 * 2³ * 3² = 5 * 8 * 9 = 360
HCF = 2² = 4
Difference = 360 - 4 = 356
8) Multiply each digit of the binary number by the corresponding power of 2, solve the powers and add them all
1111 = 1 *2³ + 1*2² + 1*2¹ + 1*2° = 8 + 4 + 2 + 1 = 15
Ans: 15
9) 36₇ = 102₅
10) 6.9163 = 6.916