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JulsSmile [24]
3 years ago
13

Find the 15th,18th,and,31st terms in the sequence A(n)=2+(n-1)(-2)

Mathematics
2 answers:
balandron [24]3 years ago
8 0

Given the sequence

a_n = 2+(n-1)(-2)=2-2(n-1)=2-2n+2= -2n+4

You can compute the k-th term by evaluating the generic term at n=k. So, the 15th, 18th and 31st terms are

a_{15}=-2(15)+4=-30+4=-26

a_{18}=-2(18)+4=-36+4=-32

a_{31}=-2(31)+4=-62+4=-58

zhenek [66]3 years ago
6 0
Substitute the values 15, 18, and 31 into the equation.
A(15)= -26
A(18)= -32
A(31)= -58
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What is the area of the trapezoid below?
goldenfox [79]

Answer:

Area 684 m squared

Step-by-step explanation:

26 + 46 = 72

72/2 = 36

36 x 19 = 684

Hope this helps!

5 0
3 years ago
PLEASE HELP <br> I forgot how to do this and it’s for a final :((
natima [27]
F(x)= 2/(x+1) and g(x)= -x2-12 => f(-7)= ? , g(2.5)= ?, g(f(- 0.5))= ?
In the expression of the function f(x) we will replace instead of x the number in bracket (-7) => f(-7) = 2/(-7+1)= 2/-6 = - 1/3
In the expression of the function g(x) we will replace instead of x number in bracket (2.5) => g(2.5) = - (2.5)squared -12= - 6.25 -12= - 18.25
Expression f(g(x)) or g(f(x)) is multiplication (composition) of the reflecting of functions f and g. We will do this in the following way => g(f(x))= g(2/(x+1))= -(2/(x+1))2 - 12= -(4/(x+1)2) -12= -4-12(x+1)2/(x+1)2=> we will replace instead of x the number in bracket (-0.5) or (-1/2) => g(f(-1/2) = -4-12((-1/2)+1)2/ ((-1/2+ 1)2= -4-12(1/2)2/(1/2)2=-4-12*(1/4)/(1/4)= (-4-3)/(1/4)=-28 
Eaisier way => f(-1/2)=2/((-1/2)+1)=2/(1/2)= 4  g(4) -(4)2-12 = -16-12= -28





8 0
4 years ago
Can you help me with this assignment​
slamgirl [31]
Where what assignment are you talking about
8 0
3 years ago
Read 2 more answers
Discrete Math (MACM 101)
Alona [7]
I hope this helps you



n!/(n-3)!=3.n!/(n-2)!


3. (n-3)!=(n-2)(n-3)!


3=n-2


n=5
7 0
3 years ago
If f(x)=4x+10, find f(2)
Genrish500 [490]

Answer:

18

Step-by-step explanation:

f(2)=4x+10

f=(4)(2)+10

f=8+10

f=18

4 0
3 years ago
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