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Sedbober [7]
3 years ago
13

50 points

Mathematics
1 answer:
aliya0001 [1]3 years ago
8 0

<span>
Use only your compass and straightedge when drawing a construction. No free-hand drawing!
SquareWe will be doing TWO constructions of a square. The first will be to construct a square given the length of one side, and the other will be to construct a square inscribed in a circle.METHOD 1:Given: the length of one side of the square
Construct: a square
STEPS:

1. Using your straightedge, draw a reference line, if one is not provided.
2. Copy the side of the square onto the reference line, starting at a point labeled A'. 
3. Construct a perpendicular at point B' to the line through.
4. <span>Place your compass point at B', and copy the side of the square onto the perpendicular. Label the end of the segment copy as point C.</span>
5. With your compass still set at a span representing AB, place the compass point at C and swing an arc to the left. 
6. Holding this same span, place the compass point at A' and swing an arc intersecting with the previous arc. Label the point of intersection as D.
7. Connect points A' to D, D to C, and C to B' to form a square.

Hope This Helps!




</span>
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Which equation could be used to calculate the sum of the geometric series? One-third + two-ninths + StartFraction 4 Over 27 EndF
kondaur [170]

Answer:

S 5 = StartFraction one-third (1 minus (two-thirds) Superscript 5 Baseline) Over (1 minus two-thirds) EndFraction

Step-by-step explanation:

Given the geometric series:

1/3+2/9+4/27+8/81+16/243

First we must know that the series is a finite series with just 5terms.

Before we can know the formula to calculate sum of the first five terms of the series, we must determine its common ratio (r) first.

r = (2/9)÷1/3 = 4/27÷2/9= 8/81÷4/27

r = 2/9 × 3/1

r = 2/3

Similarly;

r = 4/27×9/2

r = 2/3

Since all values of r is the as them the common ratio is 2/3.

If r< 1 in geometric series, then the formula for finding its sum is applicable

Sn = a(1-rⁿ)/1-r

a is the first term = 1/3

r is the common ratio = 2/3

n is the number of terms = 5

Substituting the values in the formula we have:

S5 = 1/3{1-(2/3)^5}/1-2/3

This gives the requires equation

S 5 = StartFraction one-third (1 minus (two-thirds) Superscript 5 Baseline) Over (1 minus two-thirds) EndFraction

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Step-by-step explanation:

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Is this right ? can any of you check them thanksss ​
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