1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Bezzdna [24]
3 years ago
11

Se informa que un arco eléctrico estabilizado con agua llegó la temperatura de 25600 °F. En la escala absoluta, ¿Cuál es la rela

ción entre la temperatura y la de una llama de oxiacetileno (3500 °C)?
Chemistry
1 answer:
nignag [31]3 years ago
7 0

Answer:

Explanation:

Translation:

It is reported that an electric arc stabilized with water reached the temperature of 25600 ° F. On the absolute scale, what is the relationship between the temperature and that of an oxyacetylene flame (3500 ° C)?

Solution:

Temperature of the electric arc = 25600°F

Temperature of the oxyacetylene flame = 3500°C

The absolute temperatures are usually recorded in Kelvin. In order to compare the two given temperatures, a need to convert to Kelvin arises.

From celcius to kelvin we have:

     K = 273.15 + T°C

T°C is the temperature in degree celcius

For the oxyacetylene flame:

     K = 273.15 + 3500 = 3773.15K

From fahrenheit to kelvin, we have:

    K = \frac{5}{9}(T °F – 32) + 273.15

T °F is the temperature in degree fahrenheit

For the electric arc:

    K = \frac{5}{9}(25600 – 32) + 273.15 = 14477.59K

We can see that by expressing the two temperature on the same absolute scale, an electric arc is by far hotter than an oxyacetylene flame.

You might be interested in
10-The vapor phases of liquids such as acetone and alcohol are more flammable than their liquid phases. For flammable liquids, w
pishuonlain [190]
The relationship between the evaporation rate and the likelihood that the liquid will be flammable is its flash point number (or the lowest temperature for which the liquid ignites) and its activation energy (how much energy is required to ignite it). With volatile liquids or gases these numbers seem to be lower.
5 0
3 years ago
VICHELRING CONCEN<br>1. Water is a<br>molecule.​
zaharov [31]

Explanation:

the first thing you do with your child are in a world of good and good for the first word of life will be the best thing to be the same thing you need for a long 55666666inches to be in the

3 0
4 years ago
For an aqueous solution of sodium chloride (NaCl) .Determine the molarity of 3.45L of a solution that contains 145g of sodium
worty [1.4K]
Molar mass NaCl = 58.44 g/mol

number of moles:

mass NaCl / molar mass

145 / 58.44 => 2.4811 moles of NaCl

Volume = 3.45 L

Therefore :

M = moles / volume in liters:

M = 2.4811 / 3.45

M = 0.719 mol/L⁻¹

hope this helps!
6 0
3 years ago
Hydrogen reacts with 0.771 g of carbon to form 0.90 g of a compound. What is the mass percent of hydrogen in the compound
morpeh [17]
Answer: 14.3%

Explanation: In order to find the mass percent of hydrogen in this compound, you must determine how many grams of hydrogen you'd get in 100 g of compound. 

In your case, you know that an unknown mass of hydrogen reacts with 0.771 g of carbon to form 0.90 g of hydrocarbon, which is a compound that contains only carbon and hydrogen. 

Use the total mass of the hydrocarbon to determine how many grams of hydrogen reacted with the carbon.

Now, if 0.90 g of this compound contain 0.129 g of hydrogen, it follows that 100 g of this compound will contain.

So, if 100 g of this compound contain 14.33 g of hydrogen, it follows that the mass percent of hydrogen is 14.3%


<span><span><span><span><span><span><span><span><span /></span></span></span></span></span></span></span></span><span><span>
</span></span>
4 0
4 years ago
Read 2 more answers
An aqueous potassium iodate (KIO3) solution is made by dissolving 553 grams of KIO3 in sufficient water so that the final volume
liberstina [14]

Answer:

M KIO3 = 1.254 mol/L

Explanation:

  • molarity (M) [=] mol/L

∴ w KIO3 = 553 g

∴ mm KIO3 = 214.001 g/mol

∴ volumen sln = 2.10 L

⇒ mol KIO3 = (553 g)×(mol/210.001 g) = 2.633 mol

⇒ M KIO3 = (2.633 mol KIO3 / (2.10 L sln)

⇒ M KIO3 = 1.254 mol/L

3 0
4 years ago
Read 2 more answers
Other questions:
  • In the quantum mechanical model, each allowed ____ has a precisely known energy, but the location of the electron
    11·1 answer
  • Prioritization is an example of a skill that helps you reach long term goals because
    9·1 answer
  • Who willing to talk on my question for a couple of seconds
    9·1 answer
  • How many liters of chlorine gas can react with 56.0 grams of calcium metal at standard temperature and pressure? Show all of the
    11·2 answers
  • Calculate the mass of KI in grams required to prepare 9.00 ✕ 102 mL of a 1.40 M solution
    10·1 answer
  • What is the difference between ionic formula and the molecular formula?​
    12·1 answer
  • How many atoms are in the 3.5 moles of arsenic atoms?
    6·2 answers
  • Pls help !!! Identify the independent variable and dependent variable
    5·1 answer
  • select the correct answer from each drop down menu how do you the freezing point and boiling point of a solution compare with th
    5·1 answer
  • Does Q for the formation of 1 mol of NH₃ from H₂ and N₂ differ from Q for the formation of NH₃ from H₂ and 1 mol of N₂? Explain
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!