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Bezzdna [24]
2 years ago
11

Se informa que un arco eléctrico estabilizado con agua llegó la temperatura de 25600 °F. En la escala absoluta, ¿Cuál es la rela

ción entre la temperatura y la de una llama de oxiacetileno (3500 °C)?
Chemistry
1 answer:
nignag [31]2 years ago
7 0

Answer:

Explanation:

Translation:

It is reported that an electric arc stabilized with water reached the temperature of 25600 ° F. On the absolute scale, what is the relationship between the temperature and that of an oxyacetylene flame (3500 ° C)?

Solution:

Temperature of the electric arc = 25600°F

Temperature of the oxyacetylene flame = 3500°C

The absolute temperatures are usually recorded in Kelvin. In order to compare the two given temperatures, a need to convert to Kelvin arises.

From celcius to kelvin we have:

     K = 273.15 + T°C

T°C is the temperature in degree celcius

For the oxyacetylene flame:

     K = 273.15 + 3500 = 3773.15K

From fahrenheit to kelvin, we have:

    K = \frac{5}{9}(T °F – 32) + 273.15

T °F is the temperature in degree fahrenheit

For the electric arc:

    K = \frac{5}{9}(25600 – 32) + 273.15 = 14477.59K

We can see that by expressing the two temperature on the same absolute scale, an electric arc is by far hotter than an oxyacetylene flame.

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Calculate the heat absorbed by a sample of water that has a mass of 45.00 g when the temperature increases from 21.0oC to 38.5 o
Elenna [48]

Answer:

The heat absorbed by the sample of water is 3,294.9 J

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

The sensible heat of a body is the amount of heat received or transferred by a body when it undergoes a temperature variation (Δt) without there being a change of physical state (solid, liquid or gaseous). Its mathematical expression is:

Q = c * m * ΔT

Where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case:

  • Q=?
  • m= 45 g
  • c= 4.184 \frac{J}{g*C}
  • ΔT= Tfinal - Tinitial= 38.5 C - 21 C= 17.5 C

Replacing:

Q= 4.184 \frac{J}{g*C} * 45 g* 17.5 C

Solving:

Q=3,294.9 J

<u><em>The heat absorbed by the sample of water is 3,294.9 J</em></u>

<u><em></em></u>

8 0
3 years ago
90.00 ml of 0.25 M calcium hydroxide are required to titrate 100.00 ml of hydrochloric acid. What is the molarity of the HCI?
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Answer:

50000mm u add subtract multiply divide

Explanation:

4 0
3 years ago
Would the ph at the equivalence point be acidic, basic, or neutral for each given titration?.
Lesechka [4]

Answer:

At the equivalence point, equal amounts of H+ and OH– ions will combine to form H2O, resulting in a pH of 7.0 (neutral). The pH at the equivalence point for this titration will always be 7.0, note that this is true only for titrations of strong acid with strong base.

Explanation:

3 0
2 years ago
Given the noble gas configuration of an element: [Ar] 4s2, 3d5, what is the element?
monitta

Question

<em>Given the noble gas configuration of an element: [Ar] 4s2, 3d5, what is the element? </em>

Answer:

<em>B.) Argon</em>

Hope this helps!

6 0
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A great white shark has resided at a depth where the pressure is 16 atm. If the initial volume of its swim bladder is 4 L, what
padilas [110]

Answer:

The new volume of the gas is 32L

Explanation:

P1 = 16atm

V1 = 4L

P2 = atm

V2 = ?

According to Boyle's law, the volume of a given mass of gas is inversely proportional to its volume provided the temperature remains constant.

P1 * V1 = P2 * V2

V2 = (P1 * V1) / P2

V2 = (16 * 4) / 2

V2 = 64 / 2

V2 = 32L

The new volume of the gas is 32L

6 0
3 years ago
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