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boyakko [2]
3 years ago
14

How does the Doppler effect related to the universal expanding?

Chemistry
1 answer:
tensa zangetsu [6.8K]3 years ago
7 0
The Doppler effect doesn't just apply to sound. It works with all types of waves, which includes light. Edwin Hubble used the Doppler effect to determine that the universe is expanding. Hubble found that the light from distant galaxies was shifted toward lower frequencies, to the red end of the spectrum. This is known as a red Doppler shift, or a red-shift. If the galaxies were moving toward Hubble, the light would have been blue-shifted.

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How are the sparks from a sparkler that strike your skin akin to tiny droplets of boiling water striking your skin?
skad [1K]
They both hurt and they both burn lol

they will each create a small burn on your skin if they touch you sometimes visible sometimes not. but both should burn about the same just one is water one is fire
6 0
3 years ago
How are we made of the same atoms in stars?
MariettaO [177]
Stardust atoms are heavier elements, the percentage of star mass in our body is much more impressive. Most hydrogen in our body floats around in the form of water .
3 0
3 years ago
The titration of 78.5 mL of an unknown concentration H3PO4 solution requires 134 mL of 0.224 M KOH solution. What is the concent
Katyanochek1 [597]

Answer:

0.127 M.

Explanation:

The balanced equation for the reaction is given below:

H3PO4 + 3KOH —› K3PO4 + 3H2O

From the balanced equation above, we obtained the following data:

Mole ratio of acid, H3PO4 (nA) = 1

Mole ratio of base, KOH (nB) = 3

Data obtained from the question include:

Volume of acid, H3PO4 (Va) = 78.5 mL

Molarity of acid, H3PO4 (Ma) =...?

Volume of base, KOH (Vb) = 134 mL

Molarity of base, KOH (Mb) = 0.224 M

The concentration of the acid, H3PO4 can be obtained as follow:

MaVa / MbVb = nA/nB

Ma x 78.5 / 0.224 x 134 = 1/3

Cross multiply

Ma x 78.5 x 3 = 0.224 x 134 x 1

Divide both side by 78.5 x 3

Ma = (0.224 x 134 x 1) /(78.5 x 3)

Ma = 0.127 M

Therefore, the concentration of the acid, H3PO4 is 0.127 M.

3 0
3 years ago
Given the partial equation: NO3− Pb2 → NO2 Pb4 , balance the reaction in acidic solution using the half-reaction method and fill
Fed [463]

Answer : The balanced reaction in acidic solution is,

2NO_3^-+1Pb^{2+}+4H^+\rightarrow 2NO_2+1Pb^{4+}+2H_2O

Explanation :

The given partial equation is,

NO_3^-+Pb^{2+}\rightarrow NO_2+Pb^{4+}

First we have to separate into half reaction. The two half reactions are:

NO_3^-\rightarrow NO_2

Pb^{2+}\rightarrow Pb^{4+}

Now we have to balance the half reactions in acidic medium, we get:

NO_3^-+2H^++1e^-\rightarrow NO_2+H_2O       ............(1)

Pb^{2+}\rightarrow Pb^{4+}+2e^-     ............(2)

Now we have to balance the electrons of the half reactions. When we are multiplying the equation (1) by 2, we get

2NO_3^-+4H^++2e^-\rightarrow 2NO_2+2H_2O  ...........(3)

Now we have to add both the half reactions (2) and (3), we get the final balanced chemical reaction.

2NO_3^-+1Pb^{2+}+4H^+\rightarrow 2NO_2+1Pb^{4+}+2H_2O

3 0
3 years ago
ASAP!!!!PLS I NEED IT FAST ILL MARK BRAINLIEST!!!! POR FAVOR
Nataliya [291]
The second one ......
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