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3 years ago

15

in this trial, 0.400 M NaOH was added to 40.00 ml of 0.400 M HCl. How many ml of base must be added to cause the colour to chang

e?

1 answer:

denis-greek [22]3 years ago

6 0

Answer:

The amount of Ml that is needed

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Why is electromagnetic radiation a transverse wave?

Yuki888 [10]

Since the direction of particle displacement in electromagnetic waves is also perpendicular to the direction of motion, generating the waveform of visible light and other forms of electromagnetic radiation, they are also transverse waves.

In a transverse wave, the displacement is perpendicular to the direction of motion (at an angle of 90 degrees Celsius). The direction of displacement (up and down) in the case of the ocean wave is perpendicular to the direction of wave motion (horizontally along the water), making it a transverse wave.

How far a particle has moved from its original starting position, or, in the case of an ocean wave, how high or low the water is, is measured by its displacement or amplitude.

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1 year ago

Which statement describes what it means for a planet’s orbit to be elliptical?(1 point)

sesenic [268]

Using the concepts of ellipse and the universal law of gravitation it can be found that the correct answer is:

a) The planet’s path around the sun is not a perfect circle and is shaped like an oval.

The universal gravitational law establishes that the force between two bodies is proportional to their mass and inversely proportional to the square of their distance, when one of the bodies has much greater mass than the other, the body with greater mass experiences less rotational acceleration.

In the case of the sun and the planet, the sun is many orders of magnitude more massive than the planets, therefore, it is almost fixed in the center and the lighter planets rotate around it, where the sun is in the focus of the ellipse orbit.

In the special case that the two foci coincide, there is a circular movement, but the most general is that there is some separation between the foci, so the movement is elliptical with the sun located in one of the foci.

Let's analyze the claims of this exercise

a) True. When the orbit is not a perfect circle, you have an elliptical orbit, this is the most common case.

b) False. The axis of the planet has no effect on the orbit, it affects the intensity of the radiation that reaches the planets

c) False. Circular motion is a special case of elliptical motion when the two foci coincide

d) False. The axis of the planet influences the intensity of radiation reaching the surface, but not the shape of the orbit of the plant.

Using the concepts of ellipse it can be found that the correct answer is:

a) The planet’s path around the sun is not a perfect circle and is shaped like an oval.

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3 years ago

What is the balanced form of the following equation?. Br2 + S2O32– + H2O → Br1– + SO42– + H+.

zloy xaker [14]

For the equation to be balanced, the Atom's coefficient on the left side and the right side of the equation has to be equal

so, the answer would be :

Br2 + S2032- + 5H20 -- > BR2- + 2S02- + H+

Hope this helps

8 0

3 years ago

If you have 1.00 mole of F2 at 1.00 atm of pressure and 0°C, what is the volume of F2?

ss7ja [257]

Answer:

$V=22.4L$

Explanation:

Hello,

In this case, by using the ideal gas equation, er can compute the volume of fluorine gas as shown below:

$PV=nRT\\\\V=\frac{nRT}{P}=\frac{1mol*0.082\frac{atm*L}{mol*K}+(0+273)K}{1.00atm} \\\\V=22.4L$

Best regards.

4 0

3 years ago

The cell potential of a redox reaction occurring in an electrochemical cell under any set of temperature and concentration condi

avanturin [10]

Answer : The actual cell potential of the cell is 0.47 V

Explanation:

Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

The given redox reaction is :

$Ni^{2+}(aq)+Zn(s)\rightarrow Ni(s)+Zn^{2+}(aq)$

The balanced two-half reactions will be,

Oxidation half reaction : $Zn\rightarrow Zn^{2+}+2e^-$

Reduction half reaction : $Ni^{2+}+2e^-\rightarrow Ni$

The expression for reaction quotient will be :

$Q=\frac{[Zn^{2+}]}{[Ni^{2+}]}$

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

$Q=\frac{(0.0141)}{(0.00104)}=13.6$

The value of the reaction quotient, Q, for the cell is, 13.6

Now we have to calculate the actual cell potential of the cell.

Using Nernst equation :

$E_{cell}=E^o_{cell}-\frac{RT}{nF}\ln Q$

where,

F = Faraday constant = 96500 C

R = gas constant = 8.314 J/mol.K

T = room temperature = 316 K

n = number of electrons in oxidation-reduction reaction = 2 mole

$E^o_{cell}$ = standard electrode potential of the cell = 0.51 V

$E_{cell}$ = actual cell potential of the cell = ?

Q = reaction quotient = 13.6

Now put all the given values in the above equation, we get:

$E_{cell}=0.51-\frac{(8.314)\times (316)}{2\times 96500}\ln (13.6)$

$E_{cell}=0.47V$

Therefore, the actual cell potential of the cell is 0.47 V

4 0

3 years ago