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3 years ago

Please help with this question!!!!

Mathematics

2 answers:

Molodets [167]3 years ago

7 0

Answer:

D) The number line with a solid dot and the arrow going to the right of 3.

Step-by-step explanation:

x - 5 >/= -2

x >/= 3

x is greater than or equal to 3.

Radda [10]3 years ago

5 0

For this case we must find the solution of the following inequality:

$x-5\geq-2$

So:

If we add 5 to both sides of the inequality we have:

$x-5 + 5\geq - 2 + 5\\x\geq - 2 + 5\\x\geq 3$

Thus, the solution is given by all values of x greater than or equal to 3.

Answer:

Option D

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Reflection across the y-axis<br> H(4, -3), (3, 1), J5, -1)

Stells [14]

Answer:(3,1)

Step-by-step explanation:

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3 years ago

Doubling The sum of Steves and pams ages give 38 if Pam is 10 years old how old is Steve

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Steve's age is 9

7 0

3 years ago

What is the range of the function y =^3 Square root x+ 8?

aksik [14]

Answer:

all real numbers

Step-by-step explanation:

The range of any odd root function is all real numbers, <em>cube root</em> included.

y = ∛(x+8)

is defined for all values of x. It may take on any value for y.

____

The horizontal scale of the graph is quite large so as to show the vertical extent keeps increasing. (The x-intercept is -8.)

7 0

4 years ago

Read 2 more answers

(-7x^2+3) + (4x^2+2x-1);<br> Find the sum or difference.

ivann1987 [24]

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-7x² + 3 + 4x² + 2x - 1

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-3x² + 2x + 2

hope this helps, God bless!

4 0

4 years ago

A research firm needs to estimate within 3% the proportion of junior executives leaving large manufacturing companies within thr

Y_Kistochka [10]

Answer:

972 junior executives should be surveyed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

35% of junior executives left their company within three years.

This means that $\pi = 0.35$

0.95 = 95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

To update this study, how many junior executives should be surveyed?

Within 3% of the proportion, which means that this is n for which M = 0.03. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 1.96\sqrt{\frac{0.35*0.65}{n}}$

$0.03\sqrt{n} = 1.96\sqrt{0.35*0.65}$

$\sqrt{n} = \frac{1.96\sqrt{0.35*0.65}}{0.03}$

$(\sqrt{n})^2 = (\frac{1.96\sqrt{0.35*0.65}}{0.03})^2$

$n = 971.2$

Rounding up:

972 junior executives should be surveyed.

5 0

3 years ago