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Blababa [14]
3 years ago
6

Can someone plz help me with this question

Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
5 0
Answers are A and E, this is because you can do 3:12 x 4 = 12:48 and 3:12/4 = 1:4 therefore they are all equal values
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A number x increased by 8 is greater than 26
Julli [10]

Answer:

x+8<26

Hope this helped!

3 0
3 years ago
3x exponent 2=48 solve the equation please
Sever21 [200]

Answer:

x = 4,-4

Step-by-step explanation:

8 0
3 years ago
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Plz help I will mark you brainlist plz ​
amid [387]

Here is all the work and answers for these questions they are all correct i checked them all and ive done this assignmnet before

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HELP!!!!!!!!!!!!!!!!!!!!! Do all real numbers have a decimal expansion? Select each correct answer. Some numbers, such as 1 10 ​
ankoles [38]

Answer:

1. Some numbers, such as \frac{1}{10}, have a decimal expansion that terminates.

2. All real numbers have a decimal expansion.

5. Some numbers, such as \frac{1}{18}, have a decimal expansion that repeats but does not terminate.

Step-by-step explanation:

According to the options, we have,

1. Some numbers, such as \frac{1}{10}, have a decimal expansion that terminates.

It is correct as the decimal expansion of \frac{1}{10} is 0.1, which terminates.

2. All real numbers have a decimal expansion.

This is also correct as both rational and irrational numbers can be written in decimal form.

3. Some numbers, such as \sqrt{13} do not have a decimal expansion

This is not correct as \sqrt{13}=3.605551275 i.e. it has a decimal expansion.

4. Only some real numbers have a decimal expansion.

It is not correct as 2 is correct.

5. Some numbers, such as \frac{1}{18}, have a decimal expansion that repeats but does not terminate.

It is correct as \frac{1}{18}=0.0555555.., which is non-terminating decimal expansion.

So, the correct options are,

1. Some numbers, such as \frac{1}{10}, have a decimal expansion that terminates.

2. All real numbers have a decimal expansion.

5. Some numbers, such as \frac{1}{18}, have a decimal expansion that repeats but does not terminate.

6 0
3 years ago
Answer Question number 5 <br><br>Plzzzz
Softa [21]

Step-by-step explanation:

Consider x⅓ =a

then the following expression can be written as

a²+a-2

a²+2a-a-2

a(a+2)-1(a+2)

(a+2)(a-1)

a= -2 or, a= 1

Putting the value of a

x⅓ = -2 and, x⅓ =1

6 0
3 years ago
Read 2 more answers
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