An investigation that is controlled
2 answers:
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Explanation:
The volumetric flow rate of water will be as follows.
q =
= 0.0378
Diameter =
= 0.2032 m
Relation between area and diameter is as follows.
A =
=
= 0.785 x 0.2032 x 0.2032
= 0.0324
Also, q = A × V
or, V =
=
= 1.166 m/s
As, viscosity of water = 1 cP = Pa-s
Density of water = 1000
Therefore, we will calculate Reynolds number as follows.
Reynolds number =
=
= 236931.2
Hence, the flow will be turbulent in nature.
Thus, we can conclude that the Reynolds number is 236931.2 and flow is turbulent.
Answer: A pressure of 0.681 atm would be exerted by 0.023 grams of oxygen if it occupies 31.6 mL at
.
Explanation:
Given : Mass of oxygen = 0.023 g
Volume = 31.6 mL
Convert mL into L as follows.
Temperature =
As molar mass of is 32 g/mol. Hence, the number of moles of
are calculated as follows.
Using the ideal gas equation calculate the pressure exerted by given gas as follows.
PV = nRT
where,
P = pressure
V = volume
n = number of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the value into above formula as follows.
Thus, we can conclude that a pressure of 0.681 atm would be exerted by 0.023 grams of oxygen if it occupies 31.6 mL at
.
Hope this helps, have a nice day ahead!
