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madam [21]
2 years ago
15

The molecular formula for a compound with a molar mass of 180.18g that contains 40.0% carbon, 6.7% hydrogen, and 53.3% oxygen by

mass is
Chemistry
1 answer:
maxonik [38]2 years ago
6 0

Answer:

C6H12O6

Explanation:

First you need to find the empirical formula by the percents that they're giving you. You assume that is 100 grams and if for example you have 40% of carbon you will have 40 grams of carbon.

1.Find the number of moles of each atom

C: 40g÷12g/mol= 3.33 mol

H: 6.7g÷1g/mol= 6.7 mol

O: 53.3g÷16g/mol= 3.33 mol

You divide all ratios by the minimum ratio and you obtain the empirical formula

CH2O

Since you're given the molar mass, you now have to find the molar mass of CH2O by adding the molar mass of each element present and repeated in the compound.

CH2O= 30g/mol

Now you know that the molar mass of the molecular formula we are looking for is 180.18 g/mol, and since the empirical formula is the molecular formula in its smaller ratio, by logic you can say that:

180.18g/mol ÷ 30g/mol= 6

So, you now know that the empirical formula is being multiplied by a factor of 6 to reach a compound with a molar mass of 180.18g/mol, so you multiply each subscript of the empirical formula by 6 obtaining:

C6H12O6

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Explanation:

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A chemist must dilute of aqueous sodium carbonate solution until the concentration falls to . He'll do this by adding distilled
Mademuasel [1]

The question is incomplete, complete question is :

A chemist must dilute 73.9 mL of 400 mM aqueous sodium carbonate  solution until the concentration falls to 125 mM . He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in liters. Be sure your answer has the correct number of significant digits.

Answer:

The final volume of the solution will be 0.236 L.

Explanation:

Concentration of sodium carbonate solution before dilution =M_1= 400 mM

Volume of sodium carbonate solution before dilution = V_1=73.9 mL

Concentration of sodium carbonate solution after dilution =M_2= 125 mM

Volume of sodium carbonate solution after dilution = V_2=?

Dilution equation is given by:

M_1V_1=M_2V_2

V_2=\frac{M_1V_1}{M_2}

V_2=\frac{400 mM\times 73.9 mL}{125 mM}= 236.48 mL\approx 236 mL

1 mL = 0.001 L

236 mL = 0.236 L

The final volume of the solution will be 0.236 L.

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3 years ago
a beaker of benzene is at room temperature. what is its vapor pressure. Is this vapor pressure large enough to cause the benzene
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Answer:

(1). The vapor pressure is 91 mmHg at 20°C.

(2). No, benzene will not boil at sea level.

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Benzene, C6H6 is an aromatic, liquid compound with with molar mass of 78.11 g/mol and Melting point of 5.5 °C. One of the importance or the uses of benzene is in the making of fibres and plastics.

The vapour pressure of benzene can be gotten from the table showing the vapor pressure of different liquids.

Boiling point can simply be defined as the point or the temperature in which the vapor pressure is the same with the atmospheric pressure.

The atmospheric pressure is 760mmHg, while the vapor pressure at sea level is at the temperature of 15°C which is equal to 71 mmHg( from the table showing the vapor pressure of different liquids).

71 mmHg is not equal to 760 mmHg, thus, at sea level Benzene will not boil.

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2 years ago
Where is the most of the mass of an atom located?
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