5 horses with a combined weight of 6,240 pounds
horse trailer has a limit of 8,000 pounds of horse and tacks.
Find the weight of tack, t, for each horse that Cari can allow.
5t + 6,240 < 8,000
5t + 6,240 < 8,000
- 6,240 -6,240
5t < 1,760
<span>÷5 ÷5 </span>
t < 352
Each horse can carry a tack that weighs no more than 352 pounds.
Any tack that weighs beyond <span>352 </span>pounds is will exceed the maximum carrying capacity of the horse trailer.
Answer:
= 105(x+2)/33-x
Step-by-step explanation:
Given the expression
[3(x+2)*10*7]÷70 - 2(x+2)
= 3(x+2)*70÷70 - 2(x+2)
= 210(x+2)/70-2x-4
= 210(x+2)/66-2x
= 210(x+2)/2(33-x)
= 105(x+2)/33-x
Answer:
m∠TUV = 105
Step-by-step explanation:
From the question given above, the following data were obtained:
m∠TUN = 1 + 38x
m∠NUV = 66°
m∠TUV = 105x
m∠TUV =?
Next, we shall determine the value of x. This can be obtained as illustrated below:
m∠TUV = m∠TUN + m∠NUV
105x = (1 + 38x) + 66
105x = 1 + 38x + 66
Collect like terms
105x – 38x = 1 + 66
67x = 67
Divide both side by 67
x = 67 / 67
x = 1
Finally, we shall determine the value of m∠TUV. This can be obtained as shown below:
m∠TUV = 105x
x = 1
m∠TUV = 105(1)
m∠TUV = 105
Depending on how flexibly you interpret "about 20 times larger" to mean, the answers are B and D.
Check the ratios of the larger number to the smaller number:
A: (2.01 x 10^7)/(4.25 x 10^6) = 2.01/4.25 x 10^1 = 20.1/4.25 = 4.729
B: (8.21 x 10^-3)/(4.13 x 10^-4) = 8.21/4.13 x 10^1 = 82.1/4.13 = 19.879
C: (4.91 x 10^6)/(5.09 x 10^3) = 4.91/5.09 x 10^3 = 4910/5.09 = 964.637
D: (5.97 x 10^4)/(3.12 x 10^3) = 5.97/3.12 x 10^1 = 59.7/3.12 = 19.135
Answer:
8%
Step-by-step explanation:
0.36/4.50=0.08=8%
