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Nikitich [7]
3 years ago
8

If it takes 180 stickers to cover 117 inches, how many stickers does it take to cover 5,688 inches?

Mathematics
1 answer:
Dimas [21]3 years ago
8 0
48.6153846 is the answer

I hope this helps
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Help with this algebra please :)
Ivanshal [37]
Where is the algebra.
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6 0
3 years ago
Read 2 more answers
Consider randomly selecting a student at a certain university, and let A denote the event that the selected individual
Stells [14]

Answer:

(a) P( A ∩ B )=0.5 is not possible.

(b) 0.7

(c) 0.3

(d) 0.3

(e) 0.4

Step-by-step explanation:

Given information: The alphabet A and B represents the following events

A : Individual has a Visa credit card.

B: Individual has a MasterCard.

P(A)= 0.6 and P(B)=0.4.

(a)

We need to check whether P( A ∩ B ) can be 0.5 or not.

A\cap B\subset A and A\cap B\subset B

P(A\cap B)\leq P(A) and P(A\cap B)\leq P(B)

P(A\cap B)\leq 0.6 and P(A\cap B)\leq 0.4

From these two inequalities we conclude that

P(A\cap B)\leq 0.4

Therefore, P( A ∩ B )=0.5 is not possible.

(b)

Let P(A\cap B)=0.3

We need to find the probability that student has one of these two types of cards.

P(A\cup B)=P(A)+P(B)-P(A\cap B)

Substitute the given values.

P(A\cup B)=0.6+0.4-0.3=0.7

Therefore the probability that student has one of these two types of cards is 0.7.

(c)

We need to find the probability that the selected student has neither type of card.

P(A'\cup B')=1-P(A\cup B)

P(A'\cup B')=1-0.7=0.3

Therefore the probability that the selected student has neither type of card is 0.3.

(d)

The event that the select student has a visa card, but not a mastercard is defined as

A-B

It can also written as

A\cap B'

The probability of this event is

P(A\cap B')=P(A)-P(A\cap B)

P(A\cap B')=0.6-0.3=0.3

Therefore the probability that the select student has a visa card, but not a mastercard is 0.3.

(e)

We need to find the probability that the selected student has exactly one of the two types of cards.

P(A\cap B')+P(A\cap B')=P(A\cup B)-P(A\cap B)

P(A\cap B')+P(A\cap B')=0.7-0.3

P(A\cap B')+P(A\cap B')=0.4

Therefore the probability that the selected student has exactly one of the two types of cards is 0.4.

8 0
3 years ago
Help!! I will mark brainliest!
Svetradugi [14.3K]

Answer:

1/8

Step-by-step explanation:

first multiply 2 x 2 and you get 4

then multiply 2x2x2x2x2 and you get 32

simplify 4/32

4 divided by 4 = 1

32 divided by 4 = 8

1/8

I hope this is clear!

7 0
3 years ago
Please help! <br><br> Questions above
Amiraneli [1.4K]
1.
1. \: parallelogram -  \:  \: a = \: b \times h \\ 2. \: triangles -  \:  \: a =  \frac{1}{2} b \times h \\ 3. \: trapazoid -  \:  \:  \frac{1}{2} (base1 + base2) \times h \\ 4. \: circles -  \:  \: \pi {r}^{2}
2. is the last option.
3. is d
4. is a
5 0
3 years ago
An equilateral triangle with side length 9 cm is shown in the diagram, work out the area of the triangle.
amid [387]

The answer is 35.1 cm².

Hope this helps; have a great day!

4 0
3 years ago
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