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andre [41]
4 years ago
9

A 16-foot board is to be cut into two pieces so that one piece is 4 feet longer than the other. How long will the longer piece b

e?​
Mathematics
1 answer:
zheka24 [161]4 years ago
3 0

Answer:

10 feet

Step-by-step explanation:

If x is the length of the longer piece, and y is the length of the shorter piece, then:

x + y = 16

x = y + 4

Substitute:

x + (x − 4) = 16

2x − 4 = 16

2x = 20

x = 10

The longer piece will be 10 feet long.

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Simplify the following expression. 6^1/3 divided 6^10/3<br> (with picture)
Juli2301 [7.4K]

Answer:

<u>The correct answer is A. 1/216</u>

Step-by-step explanation:

Let's simplify the expression:

6^1/3 divided 6^10/3

6^1/3 = ∛ 6 and 6^10/3 = ∛ 6¹⁰, therefore:

∛ 6 / ∛ 6¹⁰

∛ 6 * 1/∛ 6¹⁰ (Flipping the reciprocal)

∛ 6 * 1/(∛ 6 * ∛ 6⁹)

1/∛ 6⁹ (Cancelling down ∛ 6 in the numerator and denominator)

1/6³ = 1/6 * 6 * 6 = 1/216

<u>The correct answer is A. 1/216</u>

5 0
3 years ago
At the movies, you order 3 boxes of popcorn and a bottle of water. The cost of the bottle of water is $1.75. Your total cost is
anastassius [24]
X=cost of one box of popcorn.
we can suggest this equation:

3x+1.75=9.25

3x=9.25-1.75
3x=7.5
x=7.5/3
x=2.5

Answer: the equation to find the cost of one box of popcorn is 3x+1.75=9.25, and the cost of one box of popcorn is $2.5. 
8 0
4 years ago
Read 2 more answers
A geometric sequence has a first term of x-y and a common ratio of x+y. what if the third term of the sequence?
kotegsom [21]
First term t(1)=(x-y)
common ratio =(x+y)  (don't omit the parentheses)
then the nth term:
t(n)=(x-y)(x+y)^(n-1)
check:
t(1)=(x-y)(x+y)^(1-1)=(x-y)(x+y)^0=(x-y)(1)=(x-y)
t(3)=(x-y)(x+y)^(3-1)=(x-y)(x+y)^2

When n is small, t(n) can also be found by repeated multiplication of the common ratio (x+y)
6 0
4 years ago
• The scale on a map is 1 inch to 20 miles. How many
Elodia [21]

Answer:160 miles

Step-by-step explanation:

Since one inch is equal to 20 miles, multiply 8 by 20. 8*20 = 160

8 0
3 years ago
Read 2 more answers
Which operation results in an expression equivalent to ? 23y^4 - 6y^3 + 35y^2 - 20y
Tom [10]

Answer:

D. P + Q

Explanation:

Given:

P = 8y⁴ + 6y³ + 8y

Q = (5y² - 4y)(3y² + 7)

Required:

Determine which operation will give an expression equivalent to 23y⁴ - 6y³ + 35y² - 20y.

SOLUTION:

Perform each operation given to see which of them gives an expression equivalent to 23y⁴ - 6y³ + 35y² - 20y.

Q - P:

P = 8y⁴ + 6y³ + 8y

Q = (5y² - 4y)(3y² + 7)

Q - P = (5y² - 4y)(3y² + 7) - (8y⁴ + 6y³ + 8y)

(5y²(3y² + 7) -4y(3y² + 7)) - (8y⁴ + 6y³ + 8y)

(15y⁴ + 35y² - 12y³ - 28y) - (8y⁴ + 6y³ + 8y)

Open parentheses

15y⁴ + 35y² - 12y³ - 28y - 8y⁴ - 6y³ - 8y

Collect like terms

15y⁴ - 8y⁴ - 12y³ - 6y³ + 35y² - 28y - 8y

7y⁴ - 18y³ + 35y² - 36y

Therefore, P - Q does not give us an expression equivalent to 23y⁴ - 6y³ + 35y² - 20y.

PQ:

P = 8y⁴ + 6y³ + 8y

Q = (5y² - 4y)(3y² + 7) = (15y⁴ + 35y² - 12y³ - 28y)

PQ = (8y⁴ + 6y³ + 8y)(15y⁴ + 35y² - 12y³ - 28y)

=(8y⁴(15y⁴ + 35y² - 12y³ - 28y) +6y³(8y⁴ + 6y³ + 8y)(15y⁴ + 35y² - 12y³ - 28y) +8y(8y⁴ + 6y³ + 8y)(15y⁴ + 35y² - 12y³ - 28y))

= 120y⁸ . . . . .

Note: You don't need to perform this operation further anymore. It would definitely not give us the equivalent expression we are looking for. The degree of the leading term (120y⁸) is way too greater than the degree of the leading term (23y⁴) of the equivalent expression we are looking for.

Thus, PQ cannot give us an expression equivalent to 23y⁴ - 6y³ + 35y² - 20y.

P - Q:

P = 8y⁴ + 6y³ + 8y

Q = (5y² - 4y)(3y² + 7) = (15y⁴ + 35y² - 12y³ - 28y)

P - Q = (8y⁴ + 6y³ + 8y) - (15y⁴ + 35y² - 12y³ - 28y)

Open parentheses

8y⁴ + 6y³ + 8y - 15y⁴ - 35y² + 12y³ + 28y

Collect like terms

8y⁴ - 15y⁴ + 6y³ + 12y³ - 35y² + 8y + 28y

-7y⁴ + 18y³ - 35y² + 36y

Therefore, P - Q cannot give us an expression equivalent to 23y⁴ - 6y³ + 35y² - 20y.

P + Q:

P = 8y⁴ + 6y³ + 8y

Q = (5y² - 4y)(3y² + 7) = (15y⁴ + 35y² - 12y³ - 28y)

P + Q = (8y⁴ + 6y³ + 8y) + (15y⁴ + 35y² - 12y³ - 28y)

Open parentheses

8y⁴ + 6y³ + 8y + 15y⁴ + 35y² - 12y³ - 28y

Collect like terms

8y⁴ + 15y⁴ + 6y³ - 12y³ + 35y² + 8y - 28y

23y³ - 6y³ + 35y² - 20y

Therefore, P + Q will result in an expression equivalent to 23y⁴ - 6y³ + 35y² - 20y.

The answer is D.

7 0
3 years ago
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