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Arisa [49]
3 years ago
13

What are the range values of the function f(x)=-3x2+5f(x)=-3x2+5 for the domain values {-2, 0, 1}?

Mathematics
1 answer:
tatyana61 [14]3 years ago
6 0
Put the values of x from domain to the equation of the function:

f(x)=-3x^2+5\\\\for\ x=-2\to y=-3(-2)^2+5=-3(4)+5=-12+5=-7\\for\ x=0\to y=-3(0)^2+5=5\\for\ x=1\to y=-3(1)^2+5=-3+5=2
Answer: {-7; 2; 5}

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Answer:

145°

Step-by-step explanation:

There are a couple of ways you can get there:

1. ∠ACB is a right angle, 90°. Hence, ∠BAC is the complement of ∠ABC, so is ...

... ∠BAC = 90° -∠ABC = 90° -55° = 35°

Then, ∠BAC and ∠BAD are a linear pair, so total 180°. That makes ∠BAD the supplement of ∠BAC, so ...

... ∠BAD = 180° -35° = 145°

2. ∠BAD is the exterior angle at A for the triangle ABC. It will have a measure that is the sum of the opposite interior angles: given ∠ABC = 55° and right angle ACB = 90°.

... ∠BAD = 55° +90° = 145°

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3 0
3 years ago
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KATRIN_1 [288]

Answer:

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Step-by-step explanation:

So the slope is the number that comes before the x, and if the slope is -2, that means the number before is -2, and it is.

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Step-by-step explanation:

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