No I disagree, because he had 34 bottles of water at the start but, when he finished he only has 1 left. 34-1=33 so in reality he drank 33 bottles of water.

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

We have a study involving 5 different groups that each contain 9 participants (45 total). What two degrees of freedom would we r

vivado [14]

Answer:

Degree of freedoms F(4,40)

Step-by-step explanation:

Given:

There is a study which is involving 5 different groups that each contains 9 participants (totally 45)

The objective is to calculate the degree of freedoms

Formula used:

Numerator degree of freedom = k-1

denominator degree of freedom=N-K

Solution:

Numerator degree of freedom = k-1

denominator degree of freedom=N-K

Where,

K= number of groups = 5

N= total number of observations

which is given as follows,

N=45

Then,

Numerator degree of freedom = k-1

=5-1

Denominator degree of freedom = N-K

=45-5

=40

Therefore,

Degree of freedoms, F(4,40)

7 0

3 years ago

What factors multiply to -80 and add to 6

forsale [732]

80 = -1(80), -2(40), -4(20), -5(4),

Total answers include: -81, 79, -42, 16, -9, and 1.

None of them add up to 6!

Are you doing polynomial equations?

If so, you can solve it the hard way.

x^2 + 6x -80 = 0

(x^2 + 6x + 9) - 80 = 9

(x+3)^2 = 89

(x+3) = 9.43

x = 6.43

If you're not doing those then I'm afraid your question has no answer.

Hope that helps!

7 0

3 years ago

she has 6 cherry candies, 3 grape candies, and 3 lime candies. If Charlotte randomly pulls one piece of candy out of the bag, wh

yKpoI14uk [10]

Answer: $\dfrac{1}{2}$

Step-by-step explanation:

We know that probability for any event = $\dfrac{\text{Number of favorable outcomes}}{\text{Total outcomes}}$

Given : Charlotte has 6 cherry candies, 3 grape candies, and 3 lime candies.

I..e Total pieces of candies she has = 6+3+3= 12

Now , If Charlotte randomly pulls one piece of candy out of the bag, what is the probability that it will be cherry is given by :-

$\text{P(cherry)}=\dfrac{\text{Number of cherries}}{\text{Total candies}}\\\\=\dfrac{6}{12}\\\\=\dfrac{1}{2}$

Hence, the probability that it will be cherry is $\dfrac{1}{2}$ .

7 0

3 years ago