You can solve this problem by using the following rule of three:
42 s ----> 0.5 DVD
x ----> 1 DVD
Clearing x:
x = (1 / 0.5) * (42)
x = 84 s (time to complete a DVD)
Then, we have the following conversion:
1min = 60s
So:
x = (84/60)
x = 1.4 min
The rate is then:
rate = 1 / 1.4 = 0.71 DVD / minute
Answer:
Jaytree's "ripping rate" in DVDs per minute is
0.71 DVD / minute
<u>ANSWER: </u>
In 9 years, amount becomes 64 times of itself.
<u>SOLUTION:
</u>
Given, a certain sum quadruples in 3 years at compound interest, interest being compounded annually.
We know that, When interest is compound annually:
Given that,
Principal = Rs.100%
Amount = Rs.400
Rate = r%
Time = 3 years
By substituting the values in above formula, we get,
![400=100 \times\left[1+\left(\frac{R}{100}\right)\right]^{3}](https://tex.z-dn.net/?f=400%3D100%20%5Ctimes%5Cleft%5B1%2B%5Cleft%28%5Cfrac%7BR%7D%7B100%7D%5Cright%29%5Cright%5D%5E%7B3%7D)
![4=1\left[1+\left(\frac{R}{100}\right)\right]}^{3}](https://tex.z-dn.net/?f=4%3D1%5Cleft%5B1%2B%5Cleft%28%5Cfrac%7BR%7D%7B100%7D%5Cright%29%5Cright%5D%7D%5E%7B3%7D)
--- eqn 1
If sum become 64 times in the time n years then,
--- eqn 2
Using equation (1) in (2), we get
![\begin{array}{c}{\left(\left[1+\left(\frac{R}{100}\right)\right]^{3}=\left(1+\left(\frac{R}{100}\right)\right)^{2}\right.} \\ {\left[1+\left(\frac{R}{100}\right)\right]^{9}=\left(1+\left(\frac{R}{100}\right)\right)^{n}}\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bc%7D%7B%5Cleft%28%5Cleft%5B1%2B%5Cleft%28%5Cfrac%7BR%7D%7B100%7D%5Cright%29%5Cright%5D%5E%7B3%7D%3D%5Cleft%281%2B%5Cleft%28%5Cfrac%7BR%7D%7B100%7D%5Cright%29%5Cright%29%5E%7B2%7D%5Cright.%7D%20%5C%5C%20%7B%5Cleft%5B1%2B%5Cleft%28%5Cfrac%7BR%7D%7B100%7D%5Cright%29%5Cright%5D%5E%7B9%7D%3D%5Cleft%281%2B%5Cleft%28%5Cfrac%7BR%7D%7B100%7D%5Cright%29%5Cright%29%5E%7Bn%7D%7D%5Cend%7Barray%7D)
Thus, n = 9 years by comparing on both sides.
Hence, in 9 years, amount becomes 64 times of itself.
Answer:
10.5
Step-by-step explanation:
0.075*140=10.5
of= *
You know that the discrete metric only takes values of 1 and 0. Now suppose it comes from some norm ||.||. Then for any α in the underlying field of your vector space and x,y∈X, you must have that
∥α(x−y)∥=|α|∥x−y∥.
But now ||x−y|| is a fixed number and I can make α arbitrarily large and consequently the discrete metric does not come from any norm on X.
Step-by-step explanation:
hope this helps
Answer: 18,800
Step-by-step explanation: u only need 9 more numbers for 18,792 just to hit 18,800.
