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Black_prince [1.1K]
2 years ago
15

Peyton is going to invest $9,700 and leave it in an account for 16 years. Assuming the interest is compounded continuously, what

interest rate, to the nearest tenth of a percent, would be required in order for Peyton to end up with $14,100?
Mathematics
1 answer:
Mariulka [41]2 years ago
5 0

Answer: r ≈ 2.3%

Step-by-step explanation:

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Help me like right know
Ray Of Light [21]

Answer:

B. 530.66 in.

Step-by-step explanation:

The formula to find circumference is \pi r^{2}. The radius here is 13. 13 squared is 169. 169 x 3.14 is 530.66.

Hope it helps!

3 0
3 years ago
Read 2 more answers
A flagpole broke in a storm. It was originally 81 8181 feet tall. 28 2828 feet are still sticking straight out of the ground, wh
solong [7]

Answer:

The end of the flagpole is 50.79 ft away from the base of the pole.

Step-by-step explanation:

The problem is represented by the diagram below.

The broken flagpole forms the shape of a right angled triangle. We need to find one of the sides of the triangle, the adjacent (x).

The hypotenuse is the broken part of the flagpole (53 ft), while the opposite is the part of the flagpole that is still stuck to the ground (28 ft).

Using Pythagoras theorem, we have that:

hyp^2 = adj^2 + opp^2

=> 53^2 = x^2 + 28^2

3364 = x^2 + 784\\\\=> x^2 = 3364 - 784\\\\x^2 = 2580\\\\x = \sqrt{2580}\\ \\x = 50.79 ft

The end of the flagpole is 50.79 ft away from the base of the pole.

7 0
3 years ago
An insurance company states that it settles 85% of all life insurance claims within 30 days. A consumer group asks the state ins
BlackZzzverrR [31]

Using the z-distribution, it is found that since the p-value of the test is less than 0.05, we reject the null hypothesis and find that there is enough evidence to conclude that the true proportion of all life insurance claims made to this company that are settled within 30 days is less than 85%.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is not enough evidence that the proportion is below 85%, that is:

H_0: p \geq 0.85

At the alternative hypothesis, it is tested if there is enough evidence that the proportion is below 85%, that is:

H_0: p < 0.85

<h3>What is the test statistic?</h3>

The test statistic is given by:

z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}

In which:

  • \overline{p} is the sample proportion.
  • p is the proportion tested at the null hypothesis.
  • n is the sample size.

For this problem, the parameters are:

p = 0.85, n = 250, \overline{p} = \frac{203}{250} = 0.812

Hence the test statistic is:

z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}

z = \frac{0.812 - 0.85}{\sqrt{\frac{0.85(0.15)}{250}}}

z = -1.68

<h3>What is the p-value and the conclusion</h3>

Using a z-distribution calculator, with a left-tailed test, as we are testing if the proportion is less than a value, and z = -1.68, the p-value is of 0.0465.

Since the p-value of the test is less than 0.05, we reject the null hypothesis and find that there is enough evidence to conclude that the true proportion of all life insurance claims made to this company that are settled within 30 days is less than 85%.

More can be learned about the z-distribution at brainly.com/question/16313918

#SPJ1

4 0
1 year ago
The half-life of the radioactive element unobtanium-43 is 10 seconds. If 48 grams of unobtanium-43 are initially present, how ma
natka813 [3]

Answer:

At time, 10 seconds, the mass remaining is 24 grams

At time, 20 seconds, the mass remaining is 12 grams

At time, 30 seconds, the mass remaining is 6 grams

At time, 40 seconds, the mass remaining is 3 grams

At time, 50 seconds, the mass remaining is 1.5 grams

Step-by-step explanation:

Given;

initial mass of the radioactive element  = 48 grams

half life, t = 10 seconds

time of decay (s)                          remaining mass of the  radioactive element

0 ------------------------------------------------- 48 grams

10------------------------------------------------- 24 grams

20 ------------------------------------------------- 12 grams

30 -------------------------------------------------- 6 grams

40 --------------------------------------------------- 3 grams

50 ----------------------------------------------------- 1.5 grams

60------------------------------------------------------0.75 grams

Thus;

At time, 10 seconds, the mass remaining is 24 grams

At time, 20 seconds, the mass remaining is 12 grams

At time, 30 seconds, the mass remaining is 6 grams

At time, 40 seconds, the mass remaining is 3 grams

At time, 50 seconds, the mass remaining is 1.5 grams

7 0
3 years ago
Substitute for x+2y=12 and x=y-12<br><br> PLEASE HELP !
yan [13]

Answer:

x = -4, y = 8

Step-by-step explanation:

y - 12 + 2y = 12

=> 3y = 24

=> y = 8

x = 8 - 12

=> x = -4

7 0
3 years ago
Read 2 more answers
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