In the triangle ABC, the side lengths, in order from the greatest to the least, are : AC > AB > BC.
We are given a triangle. The vertices of the triangle are A, B, and C. The measures of the angles ∠A, ∠B, and ∠C are 36°, 84°, and 60°, respectively. We need to arrange the side lengths in order from the greatest to the least.
The side lengths are proportional to their opposing angles in a triangle. It means that the side opposite the largest angle is the largest side, and vice versa. The angles arranged in descending order are : 84° > 60° > 36°. The angles arranged in descending order according to the vertices are : B > C > A. The order of the lengths of the opposite sides must be the same.
Hence, the side lengths, in order from the greatest to the least, are : AC > AB > BC.
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Answer:
1. C
2. A
3. D
4. B
Step-by-step explanation:
Hopefully its correct
First, find the measure of an interior angle:
the sum of the interior angles of a polygon is (n-2)*180, n is the number of sides
for a 15-sided polygon, the sum is 13*180
each interior angle is then 13*180/15=156
the measure of each exterior angle=180-156=24
The answer to this mathematical question would be "0.4x = 4.4". I simply subtracted 1.8x to both sides of the equation (following the subtraction property of equations) and then added 4.4 to both sides of the equation (following the addition property of equations). Thus, we arrive to the answer, 0.4x = 4.4.
6*7=42
It’s the answer I guess.
