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4 years ago

1572 divide 0.3 you must show all workings

Mathematics

2 answers:

olga2289 [7]4 years ago

6 0

Answer:

1. We assume, that the number 1572 is 100% - because it's the output value of the task.

2. We assume, that x is the value we are looking for.

3. If 1572 is 100%, so we can write it down as 1572=100%.

4. We know, that x is 0.3% of the output value, so we can write it down as x=0.3%.

5. Now we have two simple equations:

1) 1572=100%

2) x=0.3%

where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:

1572/x=100%/0.3%

6. Now we just have to solve the simple equation, and we will get the solution we are looking for.

7. Solution for what is 0.3% of 1572

1572/x=100/0.3

(1572/x)*x=(100/0.3)*x - we multiply both sides of the equation by x

1572=333.33333333333*x - we divide both sides of the equation by (333.33333333333) to get x

1572/333.33333333333=x

4.716=x

x=4.716

now we have:

0.3% of 1572=4.716

Step-by-step explanation:

Reptile [31]4 years ago

5 0

Answer:

5240

Step-by-step explanation:

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Y+5=9/2(x+7) in standard form

ZanzabumX [31]

Answer:

2x-y=-1

Step-by-step explanation:

y + 9 = 2(x + 5)

y + 9 = 2x + 10 [distribute]

y = 2x + 1 [subtract 9 from both sides]

y - 2x = 1 [subtract 2x from both sides]

-2x + y = 1 [put x first]

2x - y = -1 [multiply by -1 to make x coefficient positive]

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3 years ago

A) Both data sets multiplicative relationships. In Data Set 1, y is 3 times x and in data set 2 y is 3.5 times x B) Both data sh

Sladkaya [172]

For table # 1:

x= 1 * 3.5 = 3.5

x = 2*3.5 = 7

x = 3*3.5 = 10.5

x = 4* 3.5 = 14

For table #2

x=1 * 3 = 3

x =2 * 3 = 6

x = 3*3 = 9

x = 4* 3 = 12

Hence, the data sets show multiplicative relationships:

For data set 1 is 3.5 times x, and in data set 2 y is 3 times x.

8 0

1 year ago

As part of a screening process, computer chips must be operated in an oven at 145 °C. Ten minutes after starting, the temperatur

Novosadov [1.4K]

Answer:

Step-by-step explanation:

I solved this using initial conditions and calculus, so I hope that's what you are doing in math. It's actually NOT calculus, just a concept that is taught in calculus.

The initial condition formula we need is

$y=Ce^{kt}$

Filling in our formula with the 2 conditions we are given:

$65=Ce^{10k}$ and $85=Ce^{15k}$

With those 2 equations, we have 2 unknowns, the C (initial value) and the k (the constant). We know that the initial value (or starting temp) for both conditions is the same, so we solve for C in one equation, sub it into the other equation and solve for k. If

$65=Ce^{10k}$ then

$\frac{65}{e^{10k}}=C$ which, by exponential rules is the same as