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3 years ago

1572 divide 0.3 you must show all workings

Mathematics

2 answers:

olga2289 [7]3 years ago

6 0

Answer:

1. We assume, that the number 1572 is 100% - because it's the output value of the task.

2. We assume, that x is the value we are looking for.

3. If 1572 is 100%, so we can write it down as 1572=100%.

4. We know, that x is 0.3% of the output value, so we can write it down as x=0.3%.

5. Now we have two simple equations:

1) 1572=100%

2) x=0.3%

where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:

1572/x=100%/0.3%

6. Now we just have to solve the simple equation, and we will get the solution we are looking for.

7. Solution for what is 0.3% of 1572

1572/x=100/0.3

(1572/x)*x=(100/0.3)*x - we multiply both sides of the equation by x

1572=333.33333333333*x - we divide both sides of the equation by (333.33333333333) to get x

1572/333.33333333333=x

4.716=x

x=4.716

now we have:

0.3% of 1572=4.716

Step-by-step explanation:

Reptile [31]3 years ago

5 0

Answer:

5240

Step-by-step explanation:

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3 years ago

PLEASE HELP!!!

Aliun [14]

Answer:

a. 8.75 M NaOH

b. 0.425 M CuCl₂ or 0.43 M CuCl₂

c. 0.067 M CaCO₃ or 0.07 M CaCO₃

Step-by-step explanation:

Molality is computed using the formula:

$M = \dfrac{Moles\:of\:solute}{Liters\:of\:solution}$

So first thing you need to do is determine how many moles of solute there are and divide it by the solution in liters.

Converting mass to moles, you need to get the mass of each solute per mole. You can use the periodic table to get the atomic mass (which is the grams per mole of each atom) of each of the elements involved. Then add them up and you will have how many grams per mole of each compound.

1. 35.0g of NaOH in 100ml H₂O

Element number of atoms atomic mass TOTAL

Na 1 x 22.99g/mol = 22.99g/mol

O 1 x 16.00g/mol = 16.00g/mol

H 1 x 1.01g/mol = 1.01g/mol

40.00g/mol

This means that the molecular mass of NaOH is 40.00 g/mol

Then we use this to convert 35.0g of NaOH to moles:

$35.0g \:of\:NaOH \times \dfrac{1\:mole\:of\:NaOH}{40.00g\:of\:NaOH} = \dfrac{35.0\:moles\:of\:NaOH}{40.00}=0.875\:moles\:of\:NaOH$

Now that you have the number of moles we divide it by the solution in liters. Before we can do that you have to conver 100ml to L.

$100ml\times\dfrac{1L}{1000ml} = 0.1 L$

Then we divide it:

$\dfrac{0.875\:moles\:of\:NaOH}{0.1L of solution} = 8.75M\: NaOH$

2. 20.0g CuCl₂ in 350ml H₂O

Element number of atoms atomic mass TOTAL

Cu 1 x 63.55g/mol = 63.55g/mol

Cl 2 x 34.45g/mol = 70.90g/mol

134.45g/mol

$20.g\:of\:CuCl_2\times\dfrac{1\:mole\:of\:CuCl_2}{134.45\:g\:of\:CuCl_2}=0.1488\:moles\:of\:CuCl_2$

350ml = 0.350L

$\dfrac{0.1488\:moles\:of\:CuCl_2}{0.350L\:of\:solution}=0.425M\:CuCl_2$

3. 3.35g CaCO₃ in 500ml

Element number of atoms atomic mass TOTAL

Ca 1 x 40.08g/mol = 40.08g/mol

C 1 x 12.01g/mol = 12.01g/mol

O 3 x 16.00g/mol = 48.00g/mol

100.09g/mol

$3.35g\:of\:CaCO_3\times\dfrac{1\:mole\:of\:CaCO_3}{100.09\:g\:of\:CaCO_3}=0.0335\:moles\:of\:CaCO_3$

500ml = 0.5L

$\dfrac{0.0335\:moles\:of\:CaCO_3}{0.5L}=0.067M\:CaCo_3$

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a club decides to sell t-shirts for $15.00 as a fundraiser. it costs $20.00 plus $9.00 per t-shirt to make the t-shirts. write a

Scilla [17]

The club would have to sell at least 6 t-shirts.

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meriva

Answer:

Priya is right.

Step-by-step explanation:

The factors of 80 is 1, 2, 4, 5, 8, 10, 16, 20, 40, 80

The factor pairs of 80 are

1 x 80, 2 x 40, 4 x 20, 5 x 16 and 8 x 10

If Priya picks 2 x 40, then it's prime factorisation will be, 2 x 2 x 2 x 2 x 5 = 2⁴ x 5.

If Han picks, 5 x 16 = 5 x 2 x 2 x 2 x 2 = 5 x 2⁴ = 2⁴ x 5. This is the same.

Therefore, Priya is correct, because the factors of 80 are always the same, therefore which ever you start with, you'd always get the same answer.

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morpeh [17]

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