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yarga [219]
3 years ago
15

Find the five number summary

Mathematics
1 answer:
zlopas [31]3 years ago
4 0

Minimum: 88

Quartile Q1: 131

Median: 214

Quartile Q3: 275

Maximum: 365




                                          hope it helps

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Write 400 in scientific notation.
OlgaM077 [116]

= 4 × 10 to the power of 2

Step-by-step explanation:

3 0
3 years ago
2, 2 1/2, 1 1\2, 2 whats the next number in the series
DedPeter [7]
<h3>Answer:  1</h3>

Explanation:

The jump from 2 to 2&1/2 is an increase of 1/2

2 + 1/2 = 2 & 1/2

The jump from 2 & 1/2 to 1 & 1/2 is a decrease of 1

(2 & 1/2) - 1 = (2 - 1) & 1/2 = 1 & 1/2

The jump from 1 & 1/2 to 2 is an increase of 1/2

(1 & 1/2) + 1/2 = 1 + (1/2 + 1/2) = 1 + 1 = 2

The pattern seems to be "add 1/2, subtract 1". Assuming this is the case, we would then subtract 1 from the last term we got (2) to get 2-1 = 1

7 0
3 years ago
Missy rolls two 6 sided number cubes labeled 1-6. What is the probability that both number cubes land on a prime number
WITCHER [35]

Answer:

There is a 1/4 chance of Missy rolling a prime number on both cubes.

Step-by-step explanation:

Rolling one 6-sided cube, Missy has a 3/6 or 1/2 chance of landing on a prime number because the prime numbers between 1 and 6 (inclusive) are 2,3 and 5. When Missy rolls 2, 6-sided cubes, however, the chances of that happening lessens, and we multiply 1/2 by 1/2 as a result. Therefore, when Missy rolls two 6-sided cubes, there is a 1/4 chance of Missy rolling a prime number on both cubes.

8 0
3 years ago
Solve with cramer's rule x+2y+3z=11, 2x+y+2z=10, 3x+2y+z=9
nalin [4]

Answer:

x = 2 , y = 0 , z = 3

Step-by-step explanation:

Cramer's rule is a rule through which we can find the solution of linear equation.

we have the three linear equations as

x+2y+3z=11

2x+y+2z=10

3x+2y+z=9

AX=B  

A: coefficient matrix

X= unknown vectors(x,y,z)

D = values of the linear equation (11 , 10 , 9)

now we find the determinant of the given linear equation

determinant of the matrix will be

A = \left[\begin{array}{ccc}1&2&3\\2&1&2\\3&2&1\end{array}\right]  = 1(1-4) - 2(2-6) + 3(4 - 3)

                    = 1(-3) - 2(-4) + 3(1)

                    = -3+8+3 = 8

also D\neq 0

so the determinant is Non zero we can apply Cramer's rule

we will be replacing the first column of the coefficient matrix A with the values of D

by replacing the first column we will get the value of the variable 'x'

Dx =  \left[\begin{array}{ccc}11&2&3\\10&1&2\\9&2&1\end{array}\right]   = 11(1-4) -2(10-18) + 3(20-9) = -33+16+33 = 16

x = \frac{Dx}{D}  = \frac{16}{8} = 2

similarly

Dy = \left[\begin{array}{ccc}1&11&3\\2&10&2\\3&9&1\end{array}\right] = 1(10-18) -11(2-6) + 3(18 -30) = -8 +44 -36 = 0

y = \frac{Dy}{D} = 0

Dz= \left[\begin{array}{ccc}1&2&11\\2&1&10\\3&2&9\end{array}\right] = 1(9 - 20) -2(18 - 30) + 11(4 -3) = -11 +24 +11 = 24

z = \frac{Dz}{D} = \frac{24}{8} = 3

so we have the solution as

x = 2 , y = 0 , z = 3

Therefore the solution for the given linear equations is (2,0,3).

3 0
3 years ago
PLZ HELP DUE TODAY. I WILL BE SO GRATEFUL 100 POINTS AND BRAINLIEST
motikmotik

Answer:

LCM:

7: 36

8: 6

9: 40

10: 15

GCF:

1: 10, sum is 140

2: 4, sum is 64

3: 14, sum is 84

4: 1, sum is 105

(This picture is hard to read but I am assuming that it is asking for exponents) (^ means exponent):

1: 8^7

2: 4^1

3: 10^4

Evaluating Each expression:

5: 41

6: 2

7: 27

8: 28

Algebraic expressions:

1: 5f-22

2: 48g

3: e/12

4: 3(m+7)

Please give Brainliest Answer! Thanks!

Step-by-step explanation:

6 0
2 years ago
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