Steps
8x−7y=−5
Add 7y to both sides
8x−7y+7y=−5+7y
Simplify
8x=−5+7y
Divide both sides by 8
8x
8 =−
5
8 +
7y
8
Simplify
x=
−5+7y
8
28. Surface Area
This is some sort of house-like model so for every face we see there's a congruent one that's hidden. We'll just double the area we can see.
Area = 2 × ( [14×9 rectangle] + 2[15×9 rectangle]+[triangle base 14, height 6] )
Let's separate the area into the area of the front and the sides; the front will help us for problem 29.
Front = [14×9 rectangle] + [triangle base 14, height 6]
= 14×9 + (1/2)(14)(6) = 14(9 + 3) = 14×12 = 168 sq ft
OneSide = 2[15×9 rectangle] = 30×9 = 270 sq ft
Surface Area = 2(168 + 270) = 876 sq ft
Answer: D) 876 sq ft
29. Volume of an extruded shape is area of the base, here the front, times the height, here 15 feet.
Volume = 168 * 15 = 2520 cubic ft
Answer: D) 2520 cubic ft
Answer:
The answer is below
Step-by-step explanation:
a) Let x represent the time taken to drive to see the relatives and let d be the distance travelled to go, hence:
60 mi/h = d/x
d = 60x
When returning, they still travelled a distance d, since the return trip takes 1 h longer than the trip there, therefore:
40 mi/h = d/(x+1)
d = 40(x + 1) = 40x + 40
Equating both equations:
60x = 40x + 40
60x - 40x = 40
20x = 40
x = 40/20
x = 2 h
The time taken to drive there = x = 2 hours
b) The time taken for return trip = x + 1 = 2 + 1 = 3 hours
c) The distance d = 60x = 60(2) = 120 miles
The total distance to and fro = 2d = 2(120) = 240 miles
The total time to and fro = 2 h + 3 h = 5 h
Average speed = total distance / total time = 240 miles / 5 h = 48 mi/h
6(4.5y - 12) = 9
(4.5y - 12) = 9/6
4.5y - 12 = 1.5
4.5y = 1.5 + 12
4.5y = 13.5
y = 13.5/4.5
y = 3
Answer:
<h2>This value is called the common difference</h2>
Step-by-step explanation:
The common difference is the constant value which is repeatedly added to each term in an arithmetic sequence to obtain the next term, it is basically the difference between consecutive numbers
To find the common difference we can subtract the previous term from the first time or the second to the last term from the last term, the idea of finding the common difference is basically subtracting the previous term form the subsequent term.
