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alexandr402 [8]

2 years ago

9

In twenty secands a ronot can chop half a pound of chocolate and divided it into three different equally sized contaners . How m

uch chocolate goes in each contaner

2 answers:

dalvyx [7]2 years ago

7 0

Step-by-step explanation:

you start with 1/2 lb and split it into 3s so divide by 3

1/2 * 1/3 = 1/6

each container gets 1/6 lb

konstantin123 [22]2 years ago

3 0

Answer:

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Apply the Pythagorean Theorem to find the distance between points A and C.

Rashid [163]

Answer:

a

Step-by-step explanation:

5 0

3 years ago

If Chris has 2 times as many nickels as quarters and they have a combined value of 210 cents, how many of each coin does he have

BlackZzzverrR [31]

Im pretty sure she has 6 quarters and 12 nickels since it it twice as much.

$0.25 x 6 =150

$0.5 x 12 =60

total = 210

8 0

3 years ago

Can someone help me with the bottom questions on #1-3 that are blank please?

posledela

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7 0

3 years ago

HELP!!!<br><br><br> -1/2(b-6)=5

notsponge [240]

Answer:

<h2>b=-4</h2>

Step-by-step explanation:

<h3>-1/2b+3=5</h3><h3>-1/2=5-3</h3><h3> -1/2b=2×-2</h3><h2> b=-4</h2>

5 0

2 years ago

Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y

ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; $(x^2-4)^2y'' + (x + 2)y' + 7y = 0$

The above equation can be better expressed as:

$y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0$

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

$p(x) = \dfrac{(x+2)}{(x^2-4)^2} \$

$p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \$

$p(x) = \dfrac{1}{(x+2)(x-2)^2}$

Also;

$q(x) = \dfrac{7}{(x^2-4)^2}$

$q(x) = \dfrac{7}{(x+2)^2(x-2)^2}$

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

$\lim \limits_{x \to-2} (x+ 2) p(x) = \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{1}{(x-2)^2}$

$\implies \dfrac{1}{16}$

$\lim \limits_{x \to-2} (x+ 2)^2 q(x) = \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{7}{(x-2)^2}$

$\implies \dfrac{7}{16}$

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

5 0

3 years ago