2=28 divide both get 14 . So each cd is 14$. So now 28+28=56 (4 cd's) plus 14 (1 more cd) =5 so 5 is 70.
Answer:
C) $64.49
Step-by-step explanation:
let 'x' = #minutes
cost = 29.99 + 0.3(x-500)
= 29.99 + .3(115)
= 29.99 + 34.50
= $64.49
40 I am pretty sure that is the right answer
Answer:
Probability of finding girls given that only English students attend the subject =33/59
Step-by-step explanation:
Given that during English lesson, there is no other lesson ongoing. The probability of getting girls in that class only will be equivalent to 33/59 since we expect a total of 59 students out of which 33 will be girls. Similarly, in a Maths class given that only Maths students attend the class, probability of having a girl is 29/61 since out of all students, only 29 prefer Maths and the total class attendance is 61
X will be used for the value of money she earned that week.
H represents the normal hours she worked.
D represents the number of days.
Y will represent the hours on the holiday.
Since she would be getting time and a half on the holiday, you would need to find how much time and a half pay would be first.
Time and a half = 5.50(1/2) + 5.50 = $8.25/hr for the day or holiday only.
X = 5.50(H)(D) + 8.25(Y)
Plug in your numbers
X = 5.50(7)(5) + 8.25(4)
X = 192.5 + 33
She made $225.5 that week.