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Ugo [173]
3 years ago
8

Bred has to paint a wall with 8 horizontal stripes. He has enough paint only for 5 blue, 5 red and 5 white stripes. If he can us

e at most 2 colors, how many different ways he can paint the wall.
Mathematics
1 answer:
Kay [80]3 years ago
6 0

Answer:

336

Step-by-step explanation:

Required Formulas:-

1. Number of ways to select x things out of n things = ⁿCₓ

2. Number of ways to arrange n things when a things and b things are similar = n!/(a!*b!)

Since we have to choose 8 colors and we are having 3 different colors, it is only possible when we select 2 different colors (e.g. 5 red and 3 blue). To find all possible ways we will have to find all unique arrangements of selected color.

Using formula (1), number of ways to select 2 colors out of given 3 colors = ³C₂ = 3

Using formula (2), finding all unique arrangements when 5 stripes are of one color and 3 stripes are of second color = 8!/(3!*5!) = 56

Suppose, we can choose 5 stripes from red color and 3 stripes from blue color or 5 strips from blue color and 3 strips from red color. So there are 2 possibilities of arranging every 2 colors we choose .

∴ Answer=3*56*2 = 336

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Step-by-step explanation:

Since we have given that

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Here, number of games = 2

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Since X_1\ and\ X_2 are independent variables.

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So, we get that

E(X)=0.4\times 0+0.4\times 1+0.2\times 2=0.8\\\\and Var[x]=E[x^2]-(E[x])^2\\\\E[x^2]=0\times 0.4+1\times 0.4+4\times 0.2=1.2\\\\So, Var[x]=1.2-(0.8)^2\\\\Var[x]=1.2-0.64=0.56

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and Var[y]=2×0.56=1.12

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