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ANEK [815]
3 years ago
10

Given f(x)=x^2 - 6x + 8 and g(x) = x - 2, solve f(x) = g(x) using a table of values.

Mathematics
1 answer:
Eduardwww [97]3 years ago
5 0
Set the two functions equal to each other and solve for x

x^2-6x+8=x-2
-x. -8 -x-8
x^2-7x=-10
x(x-7)=-10
x=-10 x-7=-10
+7 +7
x=-10 & x=-3
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3 years ago
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Hello, how can I do this equation?
kompoz [17]
(9^x) - 3 = 2*3^x
(9^x) - 3 - (2*3^x) = (2*3^x) - (2*3^x)
(9^x) - (2*3^x) - 3 = 0
(3^2)^x - 2*(3^x) - 3 = 0
3^(2x) - 2*(3^x) - 3 = 0
3^(x*2) - 2*(3^x) - 3 = 0
(3^x)^2 - 2*(3^x) - 3 = 0
z^2 - 2*z - 3 = 0  ............ let z = 3^x
(z - 3)(z + 1) = 0

If z-3 = 0, then z = 3 when we isolate z
If z = 3, and z = 3^x, then
z = 3
3^x = 3
3^x = 3^1
x = 1
which is a solutin in terms of x

If z+1 = 0 then z = -1
If z = -1 and z = 3^x, then there are NO solutions for this part of the equation
The quantity 3^x is never negative no matter what the x value is

---------------------------------------------------------------

Answer: x = 1
4 0
3 years ago
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