18 i looked it up hope its right
X
=
u
y
−
k
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is the answer
x= u/y - k/y
Answer:
The width of the frame is 2 inches
Step-by-step explanation:
The given dimensions of the picture = 7 inches by 7 inches
The area of the picture, A₁ = 7 in. × 7 in. = 49 in.²
The area of the given picture and the frame, A₂ = 81 square inches
Let 'w' represent the width of the frame and whereby the picture is a square, we have;
The area of the picture with the frame, A₂ = 81 in.² = (7 + w) × (7 + w)
A₂ = 81 = (7 + w) × (7 + w) = 49 + 14·w + w²
49 + 14·w + w² - 81 = 0
w² + 14·w - 32 = 0
(x + 16)·(x - 2) = 0
∴ x = -16 or x = 2
Given that 'x' is a natural number, we have;
The width of the frame, x = 2 inches.
Answer:
Step-by-step explanation:
GIVEN: dx / dt=5 in./min. and dy/ dt=−6 in./min.
FIND: dz/ dt when x=12 in. and y=9 in.
Use the Pythagorean Theorem to get the equation
x2+y2=z2
Now differentiate this equation with repect to time t getting
D{x2+y2}=D{z2} ⟶
2xdxdt+2ydydt=2zdzdt ⟶
(Multiply both sides of the equation by 1/2.)
x dx/ dt+y dy/ dt= z dz/ dt (DE)
Now let x=12 and y=9 and solve for z using the Pythagorean Theorem.
tex2html_wrap_inline125
122+92=z2 ⟶ z2=225 ⟶ z=15
Plug in all given rates and values to the equation (DE) getting
(12)(5)+(9)(−6)=(15)dz/ dt ⟶
6=15dzdt ⟶
dz/ dt=615=25 in/min.
Hope this answer helps you :)
Have a great day
Mark brainliest
