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Tasya [4]
4 years ago
15

Convert the equation to the standard form for a hyperbola 4x^2-25y^2-8x+50y-121=0

Mathematics
1 answer:
S_A_V [24]4 years ago
7 0
We have that
4x²-25y²<span>-8x+50y-121=0

</span><span>Group terms that contain the same variable, and move the constant to the opposite side of the equation
</span>(4x²-8x)+(-25y²+50y)=121

Factor the leading coefficient of each expression
4(x²-2x)-25(y²-2y)=121

Complete the square twice. Remember to balance the equation by adding the same constants to each side.
4(x²-2x+1)²-25(y²-2y+1)²=121+4-25

Rewrite as perfect squares
4(x-1)²-25(y-1)²=100

<span>Divide both sides by the constant term to place the equation in standard form</span>
(4/100)(x-1)²-(25/100)(y-1)²=100/100
(1/25)(x-1)²-(1/4)(y-1)²=1

[(x-1)²]/25-[(y-1)²]/4=1

the answer is
[(x-1)²]/25-[(y-1)²]/4=1


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Apply each of the four counting/sampling methods (with replacement and with ordering, without replacement and with ordering, wit
dusya [7]

Answer:

Step-by-step explanation:

I will illustrate this solution with a unique birthday party situation between Jane (the celebrant) and her 10 friends.

In the said party , we will assume that Jane only has 5 chocolates to share among her friends

i. Assuming that the 5 chocolates are of the same type, if she doesn't want to give any friend more than one piece of chocolate, the situation here is said to be WITHOUT REPLACEMENT & UN-ORDERED

n = 10 and k = 5

Total number of possible combinations becomes,

(\left {n} \atop {k}} \right. )=(\left {10} \atop {5}} \right. )=252

ii. Assuming that the 5 pieces of chocolate are of the same type and she is willing to give a friend more than one piece of chocolate, the situation is said to be WITH REPLACEMENT & UN-ORDERED

n = 10 and k = 5

Total number of possible combinations becomes,

(\left {n+k-1} \atop {k}} \right. )=(\left {14} \atop {5}} \right. )=2002

iii. Assuming that the 5 pieces of chocolate are of different types and she isn't willing to give any friend more than one piece of chocolate, the situation is said to be WITHOUT REPLACEMENT & ORDERED

n = 10 & k = 5

Total number of possible combinations becomes,

P\left {n} \atop {k}} \right=P\left {10} \atop {5}} \right. =30240

iv. Assuming the the 5 pieces of chocolate are of different types, if she is willing to give a friend more than one piece of chocolate, the situation is said to be WITH REPLACEMENT & ORDERED

n = 10 AND k = 5

Total number of combinations becomes

n^k=10^5=100,000

Sampling with replacement means that one friend can be sampled more than once i.e: A friend receives a piece of chocolate more than once

The order dictates how the sampling is applied.

3 0
3 years ago
Sara resd 81 pages in her book colin resd 64 pages in his book.How many more pages did sara resd than colin
Olin [163]

Answer:

Sara read 17 more

Step-by-step explanation:

81-64=17

64+17=84

7 0
4 years ago
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June has a bakery. Her rent is $750 a month. Over a month, she sells 50 cakes, 120 cupcakes and 250 dozen cookies. This costs he
Charra [1.4K]

Answer:

$2,750

Step-by-step explanation:

Total spending = Rent + Cost

= $750 + $2000

= $2750

8 0
3 years ago
Find the missing side or angle round to the nearest tenth b=15 a=30 c=29 A=[?]°
pogonyaev

Answer:

71.6056

Step-by-step explanation:

c² = a² + b² - 2abcosC°

29² = 30² + 15² - 2(30)(15)cosC°

841 = 900 + 225 - 900cosC°

-59 = 225 - 900cosC°

-284 = -900cosC°

71/225 = cosC°

cos⁻¹(71/225) = C°

C° = 71.6056

6 0
3 years ago
Anyone wanna help me?
spayn [35]
Similarities: same atomic number
Differences: they have a different number of neutrons
8 0
3 years ago
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