How many four-digit positive integers are multiples of 3?
1 answer:
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Answer: $7200
Step-by-step explanation:
Given
The policy covers the damage of $50,000 PIP
He injured 10 people including himself
The total cost of injuries is $72,000
The cost per person is $7200
The company only pays for the damaged bear by the policyholder, not by the others.
the company only pays $7200 in coverage.
So firstly, <u>the factor (4n - 5) cannot be further factored, so we will be focusing on 2n² + 5n + 3.</u>
So for this, we will be factoring by grouping. Firstly, what two terms have a product of 6n² and a sum of 5n? That would be 2n and 3n. Replace 5n with 2n + 3n:
Next, factor 2n² + 2n and 3n + 3 separately. Make sure that they have the same quantity on the inside of the parentheses:
Now we can rewrite this expression as<u> , which is your final answer.</u>