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2 years ago

Can someone please answer this question? Someone answered and they deleted their answer, so I need someone else to help me!

Mathematics

1 answer:

blsea [12.9K]2 years ago

8 0

Check the picture below.

now, notice the triangles made, 3 right triangles with legs of 5 and 4 each.

looking at quadrilateral (1), from the leg 5 units long, we have a line with a run of -1 and a rise of 3, from the leg 4 units long, we have a line with a run of 4 and a rise of -1.

Now, quadrilaterals (2) and (4) display the same lengths and rise and runs, which means they're all congruent, quadrilateral (3) has no equal.

so 1 ≅ 2 and 1 ≅ 4.

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Find the area for all of these numbers

qwelly [4]

answer : 29
………………….

6 0

2 years ago

Read 2 more answers

Match the expressions with their equivalent simplified expressions.

Tasya [4]

Answer:

$\sqrt[4]{\frac{16x^6y^4}{81x^2y^8}}\rightarrow\frac{2x}{3y}\\\sqrt[4]{\frac{81x^2y^{10}}{81x^6y^6}} \rightarrow\frac{3y}{2x}\\\sqrt[3]{\frac{64x^8y^7}{125x^2y^{10}}}\rightarrow\frac{4x^2}{5y}\\\sqrt[5]{\frac{243x^{17}y^{16}}{32x^7y^{21}}}\rightarrow\frac{3x^2}{2y}\\\sqrt[5]{\frac{32x^{12}y^{15}}{243x^7y^{10}}} \rightarrow\frac{2xy}{3}\\\sqrt[4]{\frac{16x^{10}y^{9}}{256x^2y^{17}}}\rightarrow\frac{x}{2y}$

Step-by-step explanation:

$\sqrt[4]{\frac{16x^6y^4}{81x^2y^8}} =\sqrt[4]{\frac{(2^4)(x^{6-2})(y^{4-8})}{(3^4)}} =\sqrt[4]{\frac{2^4x^4y^{-4}}{3^4}} =\frac{2xy^{-1}}{3}=\frac{2x}{3y}$

$\sqrt[4]{\frac{81x^2y^{10}}{81x^6y^6}} =\sqrt[4]{\frac{(3^4)(x^{2-6})(y^{10-6})}{(2^4)}} =\sqrt[4]{\frac{3^4x^{-4}y^{4}}{2^4}} =\frac{3x^{-1}y^1}{3}=\frac{3y}{2x}$

$\sqrt[3]{\frac{64x^8y^7}{125x^2y^{10}}} =\sqrt[3]{\frac{(4^3)(x^{8-2})(y^{7-10})}{(5^3)}} =\sqrt[3]{\frac{4^3x^6y^{-3}}{5^3}} =\frac{4x^2y^{-1}}{5}=\frac{4x^2}{5y}$

$\sqrt[5]{\frac{243x^{17}y^{16}}{32x^7y^{21}}} =\sqrt[5]{\frac{(3^5)(x^{17-7})(y^{16-21})}{(2^5)}} =\sqrt[5]{\frac{3^5x^{10}y^{-5}}{2^5}} =\frac{3x^2y^{-1}}{2}=\frac{3x^2}{2y}$

$\sqrt[5]{\frac{32x^{12}y^{15}}{243x^7y^{10}}} =\sqrt[5]{\frac{(2^5)(x^{12-7})(y^{15-10})}{(3^5)}} =\sqrt[5]{\frac{2^5x^{5}y^{5}}{3^5}} =\frac{2x^1y^{1}}{3}=\frac{2xy}{3}$

$\sqrt[4]{\frac{16x^{10}y^{9}}{256x^2y^{17}}} =\sqrt[4]{\frac{(2^4)(x^{10-2})(y^{9-17})}{(4^4)}} =\sqrt[4]{\frac{2^4x^{8}y^{-8}}{4^4}} =\frac{2x^{1}y^{-1}}{4}=\frac{x}{2y}$

Thus,

3 0

3 years ago

The Monthly Bank pays 3 percent interest, compounded monthly, on their savings accounts. The Daily Bank pays 3 percent interest,

Novosadov [1.4K]

Answer:

The amount that we should deposit in each bank is around $942.

Step-by-step explanation:

Case 1:

A=$1000

n = 12

t = 2

r = 3% or 0.03

p = ?

The compound interest formula is :

$A=p(1+\frac{r}{n})^{nt}$

Substituting values in the formula;

$1000=p(1+\frac{0.03}{12})^{12\times2}$

=> $1000=p(1.0025)^{24}$

=> $1000=1.06175p$

$p=\frac{1000}{1.06175}$

p = $941.84

Case 2:

A=$1000

n = 365

t = 2

r = 3% or 0.03

p = ?

$1000=p(1+\frac{0.03}{365})^{365\times2}$

=> $1000=p(1.0000822)^{730}$

=> $1000=1.06184p$

$p=\frac{1000}{1.06184}$

p = $941.76

The amount that we should deposit in each bank is around $942.

5 0

2 years ago

Read 2 more answers

What expression can be used for estimating 868÷29?

Lelu [443]

One expression u can use is 900÷30
Round 868 up to 900
and round 29 up is 30

4 0

2 years ago

Need help ASAP PLEASE!!!!

stepan [7]

Look at the face of the pyramid facing you. The length of the base of this pyramid is 82 m; half of that is 41 m.

If you were to draw a straight vertical line through the vertex of the pyramid, the bottom of this line would be at the very center of the base and also be 41 in perpendicular distance from any of the edges of the base of this pyramid.

Let the height of the pyramid be y, as measured upward from the center of the base of the pyramid. This center is, as before, 41 m from any side of the pyramid base, a horiz. distance.

Then, tan 52 deg = y / 41 m, and so y = height of pyramid =

(41 m)(tan 52 deg) = (41 m) (1.28) = 52.48 m

6 0

3 years ago